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9966 [12]
3 years ago
10

If a quadrilateral is a ______________________, then each _______________________ intersects the other ________________________

at its ______________________. Because this is so, we can say that the_____________________ of a ________________ also ______________________ each other.
Mathematics
1 answer:
maksim [4K]3 years ago
4 0

Answer:

If a quadrilateral is a parallelogram, then each intersects the other ________________________ at its ______________________. Because this is so, we can say that the_____________________ of a ________________ also ______________________ each other.

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Find m<1 and m<2. Justify your answer.
Natalija [7]

Answer:

M<1 80 by the corresponding angles postulate

Step-by-step explanation:

4 0
3 years ago
Y=x^2 -9x at x = 4 Find an equation of the tangent an an equation of the normal
Montano1993 [528]

The tangent line to <em>y</em> = <em>f(x)</em> at a point (<em>a</em>, <em>f(a)</em> ) has slope d<em>y</em>/d<em>x</em> at <em>x</em> = <em>a</em>. So first compute the derivative:

<em>y</em> = <em>x</em>² - 9<em>x</em>   →   d<em>y</em>/d<em>x</em> = 2<em>x</em> - 9

When <em>x</em> = 4, the function takes on a value of

<em>y</em> = 4² - 9•4 = -20

and the derivative is

d<em>y</em>/d<em>x</em> (4) = 2•4 - 9 = -1

Then use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-20) = -1 (<em>x</em> - 4)

<em>y</em> + 20 = -<em>x</em> + 4

<em>y</em> = -<em>x</em> - 24

The normal line is perpendicular to the tangent, so its slope is -1/(-1) = 1. It passes through the same point, so its equation is

<em>y</em> - (-20) = 1 (<em>x</em> - 4)

<em>y</em> + 20 = <em>x</em> - 4

<em>y</em> = <em>x</em> - 24

3 0
3 years ago
In the figure below, BD and AC are diameters of circle P.
elena-14-01-66 [18.8K]

Answer:

arc\ DC=30^o

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

The point P is the center of the circle (the drawing is not a scale )

step 1

Find the measure of angle ∠CPD

we know that

m\angle CPD+150^o=180^o ---> by supplementary angles (form a linear pair)

m\angle CPD=180^o-150^o=30^o

step 2

Find the measure of arc DC

we know that

<u><em>Central angle</em></u> is the angle that has its vertex in the center of the circumference and the sides are radii of it

so

arc\ DC=m\angle CPD ----> by central angle

therefore

arc\ DC=30^o

5 0
3 years ago
2x^4–5x^3+x^2+3x+2=?<br><br> X=5
DanielleElmas [232]

Answer:

2x^4–5x^3+x^2+3x+2=

2 \times 5^4–5 \times 5^3+5^2+3 \times 5+2

= 2 × 625 – 5 × 125 + 25 + 3 × 5 + 2

=1250 – 625 + 25 + 15 +2

= 1292 – 625

= 667

3 0
3 years ago
What is the length of arc QR? <br> A. 1/3 π<br> B. 10/3 π<br> C. 5/3 π<br> D. 20/3 π
podryga [215]
D. 20/3 I think it’s the answe
3 0
3 years ago
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