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gladu [14]
4 years ago
10

I need help on thiss pleasee asap.

Mathematics
1 answer:
OLga [1]4 years ago
5 0
Substitution. you plug in 10 for x and it equals 2 10÷5=2
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Find the 21st term in the arithmetic sequence.<br> 3, 7, 11, 15, 19, ...
NNADVOKAT [17]

The 21st term of the given arithmetic sequence is 83. The nth term of an arithmetic sequence is applied to find the required value where n = 21.

<h3>What is the nth term of an arithmetic series?</h3>

The nth term of an arithmetic sequence is calculated by the formula

aₙ = a + (n - 1) · d

Here the first term is 'a' and the common difference is 'd'.

<h3>Calculation:</h3>

The given sequence is an arithmetic sequence.

3, 7, 11, 15, 19, ....

So, the first term in the sequence is a = 3 and the common difference between the terms of the given sequence is d = 7 - 3 = 4.

Thus, the required 21st term in the sequence is

a₂₁ = 3 + (21 - 1) × 4

⇒ a₂₁ = 3 + 20 × 4

⇒ a₂₁  = 3 + 80

∴ a₂₁  = 83

So, the 21st term in the given arithmetic sequence is 83.

Learn more about the arithmetic sequence here:

brainly.com/question/6561461

#SPJ1

5 0
1 year ago
Approximately what portion of the box is shaded blue? 2/10 2/5 2/3
just olya [345]
You didn’t send an image so i’m just going to guess. I will guess 2/5
8 0
2 years ago
Question 2
Leya [2.2K]
I think it is the last one because the two top line at the top must be the same length
5 0
3 years ago
The expression represents the cost of Janelle’s cell phone bill, where m represents the number of minutes of use.0.05m + 12
Sergio039 [100]

<u>The question is </u>

What is the constant in the expression?

we know that

c=0.05m+12

where

c---------> the cost of Janelle’s cell phone bill

m-------> represents the number of minutes of use

0.05------->  represent the cost per minute (slope of the linear equation)

12 ------->  represent the constant in the expression

therefore

<u>the answer is</u>

The constant is 12


4 0
3 years ago
Read 2 more answers
1000 + 1000 = 2000
mamaluj [8]

Well , where is the question ?

7 0
3 years ago
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