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2 years ago

Which of the following statements describes how to calculate net worth?

1 answer:

5 0

The answer would be C because liabilities are considered debts you own and to calculate a net worth you must subtract all debts from your assets. Hope this helps!

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f(x)=−7x 2 +8x+2f, left parenthesis, x, right parenthesis, equals, minus, 7, x, squared, plus, 8, x, plus, 2 What is the value o

vlada-n [284]

The discriminant of the function is 120, and the function has 2 different x-intercepts

<h3>How to determine the discriminant?</h3>

The function is given as:

f(x) = -7x^2 + 8x + 2

The discriminant (d) is calculated using:

D =b^2 - 4ac

So, we have:

D = 8^2 - 4 * (-7) * 2

Evaluate

D = 120

Because the value of D is greater than 0, then the function has 2 different x-intercepts

Read more about quadratic functions at:

brainly.com/question/1214333

#SPJ1

8 0

1 year ago

Divide $28 in the ratio 5:2:7.

Nina [5.8K]

Answer:

Step-by-step explanation:

5+2+7=14

28/14=2

2*5=10

2*2=4

2*7=14

10:4:14

8 0

2 years ago

Simplify the expression:<br> 7y+9+7–2y

larisa [96]

Answer:

5y+16

Step-by-step explanation:

see image below:)

6 0

2 years ago

Read 2 more answers

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

2 years ago

Carlos has eight tickets. Carlos has 8 fewer tickets then Etta. How many tickets does Etta have?

aleksley [76]

Answer:

Step-by-step explanation:

5 0

2 years ago