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Salsk061 [2.6K]
3 years ago
8

6453 to the nearest thousand

Mathematics
2 answers:
iVinArrow [24]3 years ago
8 0

Answer:

Step-by-step explanation:

6,000

if the question is 6,500 to the nearest thousand that will be 7000. i hope this help.

Anit [1.1K]3 years ago
7 0

Answer:

6,000

Step-by-step explanation:

Look at the number beside the 6 and determine if it is greater than 5 or is 5 then you can tell if you need to round 6,000 to 7,000 or just keep 6,000.

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Simplify 5(a - <br> b. 6(a <br> b. - 7(a - 2b)
Elan Coil [88]
Not sure what you're asking. are you wanting to solve 5 ( a - b), where b equals those two things listed below? If that's the case, I can definitely help. If not, please clarify.
6 0
4 years ago
Please help !!!!!!!!!!!
insens350 [35]
(11 - 9i) - (15 - 12i) Ok so first multiple the subtraction sign into the parenthesis on the right had side of it. 
And you get -15 + 12i
So now you have 11 - 9i -15 + 12i Combine Like terms
-9i + 12i = 3i
11 - 15 = -4
So your answer is 3i - 4
Hope you find this to your liking
5 0
4 years ago
Read 2 more answers
What is 3 in 3 -in 9​
MAXImum [283]
3 plus 3 is 6 but 3 multiplies by 3 is 9, or that 3 plus 3 is 6 plus 3 is 9
8 0
3 years ago
A shipment to a warehouse consists of 4,500 MP3 players. The manager chooses a random sample of 50 MP3 players and finds 4 that
kirill [66]

Answer:

360

Step-by-step explanation:

you have to multiply 50 by 90 to get 4,500, then you multiply the number of defective ones by the same number.

8 0
3 years ago
Resolver el siguiente sistema de ecuación:
snow_tiger [21]

Answer:

x=-1\\y=4

Step-by-step explanation:

\frac{5x+2y}{3}=1

\frac{2x+y}{2}=1

Vamos a utilizar el método de sustitución. Vamos a despejar la segunda ecuación por alguna de las variables. Elegiré la y porque esta sola.

\frac{2x+y}{2}=1

Vamos a empezar por eliminar ese 2 del denominador. Para hacer esto, multiplicamos por 2 ambos lados de la ecuación.

2x+y=1*2

2x+y=2

Como vamos a despejar la y, restamos 2x en ambos lados.

y=2-2x

Listo.

------------------------------------------------------------------------

Procedemos a reemplazar el valor de y en la primera ecuación.

\frac{5x+2y}{3}=1

\frac{5x+2(2-2x)}{3}=1

\frac{5x+4-4x}{3} =1

Procedemos a operar términos semejantes.

\frac{x+4}{3} =1

Nos deshacemos del 3 multiplicando.

x+4=1*3\\x+4=3

Restamos 4

x=3-4\\x=-1

-----------------------------------------------------------------------------

Una vez encontrado el valor de x, procedemos a reemplazar en cualquier ecuación para encontrar el valor de y. Usaré la segunda ecuación.

\frac{2x+y}{2}=1

\frac{2(-1)+y}{2}=1

Procedemos a resolver;

\frac{-2+y}{2} =1

Multiplicamos por 2.

-2+y=1*2

-2+y=2

Sumamos 2

y=2+2\\y=4

-------------------------------------------------------------------------------

Para comprobar que los valores son correctos, reemplazamos ambos valores en cualquier ecuación y el resultado debe ser igual.

Usaré la primera.

\frac{5x+2y}{3} =1

\frac{5(-1)+2(4)}{3} =1

Resolvemos;

\frac{-5+8}{3} =1

\frac{3}{3}=1

1=1

6 0
4 years ago
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