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3 years ago

Find the first five multiples of number five

Mathematics

2 answers:

Harlamova29_29 [7]3 years ago

6 0

Answer:

5, 15, 20 , 25 ,30.

Step-by-step explanation:

ASHA 777 [7]3 years ago

3 0

5,10,15,20,25,30
you would count by 5’s till you get 5 answers

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a guy walks into a store and steals $100 from register, comes back and buys $70 worth of merchandise, pys for it with same $100

kompoz [17]

<span>Let's do this step by step, we know that the guy steals $ 100 So it would be - $ 100 for the store. The men buy $ 70 merchandise WITH THE MONEY THAT HE STOLE, but the money that he stole CAME BACK to the store So up to this poin, : - $ 100 + $100 - $ 70 = - $ 70 for the store After that , the store give $ 30 cash back, So in the and : - $ 70 - $30 = - $ 100 lost for the store </span>

6 0

3 years ago

Please help!! worth 20 points !!

MaRussiya [10]

Answer:

So you have it right. 15 5/7 in

Step-by-step explanation:

C = πd

All you can do now is substitute what has been given

Diameter = 5

Pi = $\frac{22}{7}$

C = $\frac{22}{7}$ * 5

Multiply from across

22 * 5 = 110 ( numerator)

7 * 1 = 7 (denominator)

110/7 (improper fraction) = 15.71428571428571 ( as a decimal) = 15 5/7 ( as a mixed number)

Ik its 15 5/7 because 1. the 15 wont change, and 2 5/7 = 0.7142857142857143, which is the same one as above

Hope this helped!

Have a supercalifragilisticexpialidocious day!

4 0

3 years ago

Solve the system by the elimination method. -2x + y + 6 = 0 2x + y - 8 = 0 When you eliminate x, what is the resulting equation?

Natali5045456 [20]

For this case we have the following system of two equations with two unknowns:

$-2x + y + 6 = 0\\2x + y-8 = 0$

Adding both equations we have to eliminate the variable "x":

$y + y + 6-8 = 0$

Adding common terms, keeping in mind that different signs are subtracted and the sign of the major is placed:

$2y-2 = 0\\2y = 2$

Answer:

$2y = 2$

Option A

5 0

3 years ago

Which function is equivalent to 3x^2+x-10

rodikova [14]

Answer:

Step-by-step explanation:

4 0

3 years ago

There are some nickels, dimes, and quarters in a large piggy bank. For every 2 nickels there are 3 dimes. For every 2 dimes ther

rodikova [14]

Answer: a) Number of nickels, dimes, and quarters are 80, 120, 300 respectively.

b) The coins are worth of 91 dollars i.e. $91 in the piggy bank.

Explanation:

Since we have given that

For every 2 nickels there are 3 dimes ,

So, their ratio will be 2:3

and for every 2 dimes there are 5 quarters.\,

So, their ratio will be 2:5

Now, we'll first find the ratio of nickles to dimes to quarters i.e.

Nickle Dimes Quarters

2 3

2 5

So, it becomes ,

Nickle : Dimes : Quarters

2×2 : 3×2 : 3×5

4 : 6 : 15

Now, let the number of nickle be 4x

Let the number of dimes be 6x

Let the number of quarters be 15x

According to question,

$4x+6x+15x=500\\\\25x=500\\\\x=\frac{500}{25}=20$

So, number of nickels is given by

$4x=4\times 20=80$

Number of dimes is given by

$6x=4\times 20=120$

Number of quarters is given by

$15x=4\times 20=300$

As we know that

$1\ nickel=5\ cents\\\\1\ dime=10\ cents\\\\1\ quarter=25\ cents$

So, According to our question, we get

$80\times 5+120\times 10+300\times 25=400+1200+7500=9100\ cents\\\\1\ cent=0.01\ dollar\\\\9100\ cents=9100\times 0.01\ dollars=91\ dollars.$

Hence,

a) Number of nickels, dimes, and quarters are 80, 120, 300 respectively.

b) the coins are worth of 91 dollars i.e. $91 in the piggy bank.

7 0

3 years ago

Find the first five multiples of number five​

Find the first five multiples of number five