Solve the equation. You may find using algebra tiles helpful in solving this problem.

Mathematics

1 answer:

kicyunya [14]3 years ago

5 0

Answer:

x = -4

Step-by-step explanation:

x + 4 = -x - 4

adding both side with x

x + x + 4 = x - x - 4

2x + 4 = -4

give both side (-4)

2x + 4 - 4 = -4 - 4

2x = -8

x = -8/2 = -4

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Step-by-step explanation:

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2 years ago

Solve for t: 3t + 4 = -4

Vinvika [58]

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3 years ago

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andre [41]

Answer:

$f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}$

Step-by-step explanation:

Each vertical asymptote corresponds to a zero in the denominator. When the function does not change sign from one side of the asymptote to the other, the factor has even degree. The vertical asymptote at x=-4 corresponds to a denominator factor of (x+4). The one at x=2 corresponds to a denominator factor of (x-2)², because the function does not change sign there.

Each zero corresponds to a numerator factor that is zero at that point. Again, if the sign doesn't change either side of that zero, then the factor has even multiplicity. The zero at x=1 corresponds to a numerator factor of (x-1)².

Each "hole" in the function corresponds to numerator and denominator factors that are equal and both zero at that point. The hole at x=-3 corresponds to numerator and denominator factors of (x-3).

Taken altogether, these factors give us the function ...

$\boxed{f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}}$