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uranmaximum [27]
3 years ago
7

What is the common ratio between 16,8,4,2

Mathematics
1 answer:
tia_tia [17]3 years ago
8 0
The common ratio is 2.
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Find the volume of the composite figure. please!
Jet001 [13]
Im not shore but i think it is 38?<span />
7 0
3 years ago
Plz help, The graph of y = f(x) is shown below. What are all of the real solutions of f(x) = 0?
8_murik_8 [283]

Answer:

The real solutions of f(x)=0 are: 0, 2, 5, 6

Step-by-step explanation:

We are given:

The graph of y = f(x)

We need to find all of the real solutions of f(x) = 0?

By looking at the graph we need to find the values of y when x =0

Looking at the graph, when x=0 we get

0, 2,5 and 6

So, the real solutions of f(x)=0 are: 0, 2, 5, 6

I am attaching the figure, that determines the answers.

8 0
3 years ago
PLEASE HELP<br> THANK YOU
Anastasy [175]
-5 since A is at 5 you would take negative A and get -5
7 0
4 years ago
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 44,663 miles, with a standard
expeople1 [14]

Answer:

The probability is  P(| \= X- \mu|  < 199 ) = 0.733

Step-by-step explanation:

From the question we are told that

   The mean mileage of a tire is   \mu =  44663

   The standard deviation is  \sigma  =  2594

   The sample size is  n  =  209

 Generally the standard error of mean is mathematically represented as

    \sigma_{x}  =  \frac{\sigma}{\sqrt{n} }

=>  \sigma_{x}  =  \frac{2594}{\sqrt{209} }  

=>  \sigma_{x}  =   179.4      

Generally  the probability that the sample mean would differ from the population mean by less than 199 miles  is mathematically represented as

     P(| \= X- \mu| < 199 ) = P(|\frac{\= X - \mu}{ \sigma_{x}}|  <  \frac{199}{ 179.4})

\frac{\= X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ \= X )

=>  P(| \= X- \mu|  < 199 ) = P(|Z|  <  \frac{199}{ 179.4})

=>   P(| \= X- \mu|  < 199 ) = P(|Z|<  1.11)

=>   P(| \= X- \mu| < 199 ) = P(-1.11  \le  Z \le 1.11 )

=>   P(| \= X- \mu|  < 199 ) = P(Z  \le 1.11 ) - P( Z \le -1.11 )

From the z  table  the area under the normal curve to the left corresponding to 1.11 and -1.11 is  

        P(Z  \le 1.11 ) = 0.8665

and

       P(Z  \le - 1.11 ) = 0.1335

So

    P(| \= X- \mu| < 199 ) = 0.8665 - 0.1335

=>  P(| \= X- \mu|  < 199 ) = 0.733

8 0
3 years ago
Which of these is not a method to solve systems of
Allushta [10]

Answer:

Fourth option

Step-by-step explanation:

The answer is the fourth option "difference of squares method." It's not the first option because the substitution method is when you pick one of the equation in a system of equations, solve it for a variable and then plug the variable into the other equation to help solve. It's not the second option because the graphing method is used to solve a system of equations by graphing the equations on the same coordinate plane, it's not the third option because the addition method is also known as the elimination method which is the third method to solving a system of equations. Therefore your answer is the fourth option.

Hope this helps.

5 0
3 years ago
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