All categories

3 years ago

How do you find the area of triangles turned into parallelograms❓

Mathematics

1 answer:

AysviL [449]3 years ago

3 0

Answer:

add please give me a heart and all the stars thanks. and love you all!!

Step-by-step explanation: you add the parallelograms together

You might be interested in

I hate this pain i got through i just cant anymore... y+50=700

DiKsa [7]

Answer:

y=650

Step-by-step explanation:

Just subtract 50 from each side

And Yes, please

5 0

3 years ago

Read 2 more answers

What is the output of the expression 14/3

hram777 [196]

I did

14/3=4 2/3

so the final answer is 4 and 2/3

8 0

3 years ago

The value of 12pi over 10pi times 5pi Over 6pi is closest to the whole number (blank). Find the blank

lisov135 [29]

Given:

The expression is

$\dfrac{12\pi}{10\pi}\times \dfrac{5\pi}{6\pi}$

To find:

The value of the given expression closest to the whole number.

Solution:

We have,

$\dfrac{12\pi}{10\pi}\times \dfrac{5\pi}{6\pi}$

Cancel out the common factors from each fraction.

$=\dfrac{6}{5}\times \dfrac{5}{6}$

$=\dfrac{6\times 5}{5\times 6}$

$=\dfrac{30}{30}$

$=1$

Therefore, the value of the given expression is 1.

6 0

2 years ago

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

7 0

2 years ago

What is the area of the figure below?

svetlana [45]

24 cm sq is the answer

8 0

2 years ago

Read 2 more answers