Answer:49 sec
Step-by-step explanation:
Given
Maximum speed to reach is 183.58 mi/h
Length of course is 5 mi
acceleration rate is defined by 60mi/h in 4 sec
therefore acceleration(a)


To reach a speed of 183.58mi/h with an acceleration of 
Using equation of motion
v=u+at


t=0.00339 hours
t=12.23 s reach maximum speed
To complete course it takes


t=0.01360 hour
or 
Answer:
I can
Step-by-step explanation:
I'm taking precalculus currently
Answer:
C) 3(x+7)²
Step-by-step explanation:
Answer:
14
Step-by-step explanation:
7*3=21
2/3 of 21 is 14 so she saved 14 dollars
Answer:
x=2 and y=1
Step-by-step explanation:
Add the two equations to remove "y" and solve for x:
4x+8y=16
6x-8y=4
________
10x=20
x=2
Plug x=2 into one of the original equations to get the value of "y":
4x+8y=16
4(2)+8y=16
8+8y=16
8y=8
y=1
Therefore, x=2 and y=1