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3 years ago

PLSSS HELP!! WILL GIVE BRAINLIEST!

Mathematics

2 answers:

Advocard [28]3 years ago

8 0

Answer:

Although it's blurry, I believe y is equal to 3.

Step-by-step explanation:

You can see where x (the horizontal line) = 7, then go up to where the diagonal line meets that point, which is at y (the vertical line) = 3.

miv72 [106K]3 years ago

5 0

Answer:

<h2>y = $2 \frac{11}{12}$ gallons</h2>

Step-by-step explanation:

The water run at a constant speed with the slope of 5/12.

Slope-intercept form would be y = 5/12x.

So if we were to plug it in the equation,

y = 5/12 (7) = 35/12 or 2 11/12.

Hope this helps ;D

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Please help!!!!!!! Will mark brainliest

netineya [11]

Answer:

$\displaystyle 5$

Step-by-step explanation:

$\displaystyle ±7 = \sqrt{49} \\ \\ -7 = x + 2\:\:AND\:\:7 = x + 2 \\ \\ -9, 5 = x$

Sinse you want the POSITIVE solution, your answer is 5.

I am joyous to assist you at any time.

7 0

2 years ago

Helppppp pleazeee!!!

Tomtit [17]

I believe the answer is Chord AB

3 0

2 years ago

Read 2 more answers

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2

Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is $\frac{1}{20000}$

Probability of getting second prize is $\frac{2}{20000}$

Probability of getting third prize is $\frac{20}{20000}$

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

$\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10$

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is $\frac{19977}{20000}$

The expected value is

$E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25$

$E=\frac{1000+600+200-4994.25}{20000}$

$E=\frac{-3194.25}{20000}$

$E=-0.159$

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0

3 years ago

A function is shown in the table.

Anna71 [15]

<span>Given:
x g(x)
−3 17
−1 −3
0 −4
2 13

The true statement for the given function is:
</span><span>The function is decreasing from x = −3 to x = −1.
</span><span>
As you can see, when x = -3 the corresponding value of the function is 17 but when x = -1 the corresponding value is -3. There is a decrease of 20. </span>→<span> 17 - 20 = -3

</span>

3 0

3 years ago

Read 2 more answers

Divide: 48xy4 - 72xy2

Maurinko [17]

12xy2 good luck though :)

5 0

3 years ago