Which digit is in the tenths place on 48.92

In a sample of 115 115 curtains, the average length was found to be 32.2in. 32.2 ⁢ in. With a standard deviation of 0.8 0.8 . Gi

pentagon [3]

Answer:

The point estimate for the population standard deviation of the length of the curtains is 8.58in.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$s = 0.8, n = 115$

The point estimate for the population standard deviation of the length of the curtains is $\sigma$ . So

$s = \frac{\sigma}{\sqrt{n}}$

$\sigma = s\sqrt{n}$

$\sigma = 0.8\sqrt{115}$

$\sigma = 8.58$

The point estimate for the population standard deviation of the length of the curtains is 8.58in.

3 0

3 years ago

I need help

agasfer [191]

(0,4) hope this helps

7 0

3 years ago

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20 POINTS WILL GIVE BRAINLIEST HELP QUICKLY!!

SVETLANKA909090 [29]

Answer:

1.function 1 has a greater rate of change than function 2

3. Function 1 has a greater y-intercept than function 2

Step-by-step explanation:

Using the table we can find the slope using

m = (y2-y1)/ (x2-x1)

m = (29-5)/ (8-0)

= 24/8

= 3

The rate of change for the table is 3

The y intercept is (0,5)

Using the graph (0,-1) and (2,0)

m = (y2-y1)/ (x2-x1)

m = (0--1)/ (2-0)

= (0+1)/2

= 1/2

The y intercept is (0,-1)

Since 3>1/2 , function 1 has a greater rate of change than function 2

Since 5>-1, function 1 has a greater y-intercept than function 2

8 0

3 years ago

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Jeff uses 3 fifty-size strips to model 3/5. He wants to use tenth-size strips to model an equivalent fraction. How many tenth-si

UNO [17]

He will need 6 tenth-size strips.

6 0

3 years ago

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Time spent using e-mail per session is normally distributed, with mu equals 11 minutes and sigma equals 3 minutes. Assume that

liq [111]

Answer:

a) 0.259

b) 0.297

c) 0.497

Step-by-step explanation:

To solve this problem, it is important to know the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 11, \sigma = 3$