What is the closed linear form for this sequence given a1 = 0.3 and an 1 = an 0.75?

Solve this plss I need help :c<br>2/3(3х + 9) = - 2(2x + 6)<br>

Lena [83]

Answer:

$x=-3$

Step-by-step explanation:

$\frac{2}{3}\left(3x+9\right)=-2\left(2x+6\right)$

Expand:

$\frac{2}{3} *3x+\frac{2}{3} *9=-2*2x+(-2)(6)$

$2x+6=-4x-12$

Subtract 6 from both sides:

$2x+6-6=-4x-12-6$

$2x=-4x-18$

Add 4x to both sides:

$2x+4x=-4x-18+4x$

$6x=18$

Divide both sides by 6:

$\frac{6x}{6}=\frac{-18}{6}\\$

$x=-3$

7 0

3 years ago

Read 2 more answers

My

Liula [17]

Answer:

25min

Step-by-step explanation:

40 is the unit rate so 40 words per minute so it's 25 because 1000÷(40)*

(the unit rate)*. Sorry if I'm worng.

4 0

4 years ago

42 students are going on a field trip the students are divided into groups of four students. How many groups of four students wi

PolarNik [594]

10 groups of 4 and 1 group of 2

8 0

3 years ago

GUYS PLEASE ANSWER URGENT!!!!!!!!!!!!!!!!!!!!!!!!!!!!

iragen [17]

Answer:

Step-by-step explanation:

17 : i 12x^2(4x−3) ,

ii : 5x(x−3y) ,

iii: 5xy^2z(3x^2−5z^2)

18) since the two polynomial are equal then :

2x^3+ax^2+3x-5 = x^3+x^2-2x+a same remainder x-2 then x=2

2(2)^3+a(2)^2+3(2)-5=(2)^3+(2)^2-2(2)+a solve for a

-3a=9

a=-3

18 ) x^3+y^3 -125+15xy

x^3+y^3-(5)^3-3(x)(y)(-5) then factorize x^3+y^3

(x+y)(x^2-xy+y^2)- (5)(5)^2-3(x)(y)(-5) common factor x+y-5

(x+y-5)(x^2-xy+y^2-5^2-3xy given x+y=5

5-5( x^2-xy+y^2-25-3xy) = 0

the value of the expression equal to zero

8 0

3 years ago

There is 3/4 pound of cream in a containwr. Julian will use 3/8 pound of cream to make crème brûlée. What fraction of a pound of

Ksivusya [100]

Answer:

$\frac{3}{8}\ pound$ of cream will remain in the container.

Step-by-step explanation:

Given:

Amount of cream in the container = $\frac{3}{4}\ pound$

Amount of cream used to make crème brûlée = $\frac{3}{8}\ pound$

We need to find the amount of cream remain in the container.

Solution:

Now we can say that;

the amount of cream remain in the container is equal to Amount of cream in the container minus Amount of cream used to make crème brûlée.

framing in equation form we get;

amount of cream remain in the container = $\frac{3}{4}-\frac{3}{8}$

Now we will make the denominator common using LCM we get;

amount of cream remain in the container = $\frac{3\times2}{4\times2}-\frac{3\times1}{8\times1}= \frac{6}{8}-\frac{3}{8}$

Now denominators are common so we will solve the numerators.

amount of cream remain in the container = $\frac{6-3}{8}=\frac{3}{8}\ pound$

Hence $\frac{3}{8}\ pound$ of cream will remain in the container.

7 0

3 years ago