(2n + 5k)^2 = (2n + 5k)(2n + 5k)
Here we need to use FOIL
First - 2n * 2n = 4n^2
Outside - 2n * 5k = 10nk
Inside - 5k * 2n = 10nk
Last - 5k * 5k = 25k^2
That gives us 4n^2 + 10nk + 10nk + 25k^2, we can combine 10nk + 10nk to give 20nk, and a final equaion of 4n^2 + 20nk + 25k^2
Answer:
-6 and 6
Step-by-step explanation:
Because one is a positive and one is negative, they cancel each other out equaling 0.
Answer: C=4
Step-by-step explanation:
5(5c-1)-1 = 23c + 6
1. Using PEMDAS. You know to do parenthesis first which is 5(5c-1)
Using distributive property you will get 25c-1-1 = 23c + 6
2. Simply on both sides and get 25c-2=23c+6
3. Using the rule that whatever you do on one side of the equal sign, you do on the other you can subtract 23c from both sides and get 2c-2=6. Then add 2 on both sides and get 2c=8
4. Divide both sides by 2 to get rid of the 2 and you get c=4
