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dedylja [7]
3 years ago
15

The director of admissions at Kinzua University in Nova Scotia estimated the distribution of student admissions for the fall sem

ester on the basis of past experience.
Admissions Probability 1,080 0.4 1,380 0.1 1,540 0.5

1. What is the expected number of admissions for the fall semester? Expected number of admissions 1340

2. Compute the variance and the standard deviation of the number of admissions. (Round your standard deviation to 2 decimal places.) Variance Standard deviation
Mathematics
1 answer:
Lorico [155]3 years ago
8 0

Answer:

1. 1340

2. Variance = 47200, standard deviation = 217.25556

Step-by-step explanation:

1-

If X is the random variable that give the number of admissions, then the expected number of admissions<em> E[X]</em> for the fall semester is

1080*P(X=1080)+1380*P(X=1380)+1540*P(X=1540) =

1080*0.4+1380*0.1+1540*0.5 = 1340

2-

The <em>variance</em> is defined as

\sigma^2=E[X^2]-(E[X])^2}

We have

E[X^2]=(1080)^2*0.4+(1380)^2*0.1+(1540)^2*0.5=1842800

whereas

(E[X])^2=(1340)^2=1795600

So the variance equals

\sigma^2=1842800-1795600=47200

The <em>standard deviation is just the square root of the variance</em>, so, the standard deviation is

\sigma=\sqrt{47200}=217.25556

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Find the value of x and y
vova2212 [387]

let's first off take a look at the <u>tickmarks</u>, three <u>side tickmarks</u>, so all those 3 sides are equal, all have a length of y - 25, so is an equilateral triangle.

there are two <u>angle tickmarks</u>, meaning those two angles are equal, wait a second! if those two angles are equal, that means is an isosceles triangle.

now, in an equilateral triangle, all sides are equal, but also all angles are equal, since the sum of all interior angles is 180°, then each angle is really 60°.

let's notice that angle on the upper-left-corner, is a right-angle, but 60° are on the equilateral triangle, and so the remaining 30° must be on the isosceles triangle.

the isosceles triangle has then a vertex of 30°, and twin angles, the twin angles let's say are each a° so then

30° + a° + a° = 180°

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now, let's recall, the isosceles triangle has twin angles but it also has twin sides, so the side "x" and the side with the tickmark are equal.

well, we know that y = 75, so the sides with the tickmark are then (75) - 25 = 50 = x.

5 0
3 years ago
The measure of an interior angle of a regular octagon is how many degrees greater than the measure of an interior angle of a reg
harina [27]

Answer:

Step-by-step explanation:

Sum of interior angle of any polygon = 180* (n- 2 )

Here, n= number of sides

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In regular octagon, all the angles are congruent,

So, measure of an interior angle of regular octagon = 1080/8 =  135°

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In regular hexagon, all the angles are congruent,

So, measure of an interior angle of regular hexagon = 720/6 =  120°

The measure of an interior angle of a regular octagon is  greater than the measure of an interior angle of a regular hexagon by 15°

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4 years ago
The equation of function h is h... PLEASE HELP MATH
Flura [38]

Answer:

Part A: the value of h(4) - m(16) is -4

Part B: The y-intercepts are 4 units apart

Part C: m(x) can not exceed h(x) for any value of x

Step-by-step explanation:

Let us use the table to find the function m(x)

There is a constant difference between each two consecutive values of x and also in y, then the table represents a linear function

The form of the linear function is m(x) = a x + b, where

  • a is the slope of the function
  • b is the y-intercept

The slope = Δm(x)/Δx

∵ At x = 8, m(x) = 2

∵ At x = 10, m(x) = 3

∴ The slope = \frac{3-2}{10-8}=\frac{1}{2}

∴ a = \frac{1}{2}

- Substitute it in the form of the function

∴ m(x) = \frac{1}{2} x + b

- To find b substitute x and m(x) in the function by (8 , 2)

∵ 2 = \frac{1}{2} (8) + b

∴ 2 = 4 + b

- Subtract 4 from both sides

∴ -2 = b

∴ m(x) = \frac{1}{2} x - 2

Now let us answer the questions

Part A:

∵ h(x) = \frac{1}{2} (x - 2)²

∴ h(4) = \frac{1}{2} (4 - 2)²

∴ h(4) = \frac{1}{2} (2)²

∴ h(4) =  \frac{1}{2}(4)

∴ h(4) = 2

∵ m(x) = \frac{1}{2} x - 2

∴ m(16) =  \frac{1}{2} (16) - 2

∴ m(16) = 8 - 2

∴ m(16) = 6

- Find now h(4) - m(16)

∵ h(4) - m(16) = 2 - 6

∴ h(4) - m(16) = -4

Part B:

The y-intercept is the value of h(x) at x = 0

∵ h(x) = \frac{1}{2} (x - 2)²

∵ x = 0

∴ h(0) = \frac{1}{2} (0 - 2)²

∴ h(0) =  \frac{1}{2} (-2)² =  

∴ h(0) = 2

∴ The y-intercept of h(x) is 2

∵ m(x) = \frac{1}{2} x - 2

∵ x = 0

∴ m(0) = \frac{1}{2} (0) - 2 = 0 - 2

∴ m(0) = -2

∴ The y-intercept of m(x) is -2

- Find the distance between y = 2 and y = -2

∴ The difference between the y-intercepts of the graphs = 2 - (-2)

∴ The difference between the y-intercepts of the graphs = 4

∴ The y-intercepts are 4 units apart

Part C:

The minimum/maximum point of a quadratic function f(x) = a(x - h) + k is point (h , k)

Compare this form with the form of h(x)

∵ h = 2 and k = 0

∴ The minimum point of the graph of h(x) is (2 , 0)

∵ k is the minimum value of f(x)

∴ 0 is the minimum value of h(x)

∴ The domain of h(x) is all real numbers

∴ The range of h(x) is h(x) ≥ 2

∵ m(8) = 2

∵ m(14) = 5

∵ h(8) = \frac{1}{2} (8 - 2)² = 18

∵ h(14) = \frac{1}{2} (14 - 2)² = 72

∴ h(x) is always > m(x)

∴ m(x) can not exceed h(x) for any value of x

<em>Look to the attached graph for more understand</em>

The blue graph represents h(x)

The green graph represents m(x)

The blue graph is above the green graph for all values of x, then there is no value of x make m(x) exceeds h(x)

7 0
3 years ago
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