Answer:
Step-by-step explanation:
A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your
b2n+32n+3 = 2 (2n+2)22 b2n+12n+1
your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:
1. Either placing a 1 in available n places (because you can't place it at the end)
2. or by placing a zero in available n+1 places.
0 ϵ P
x ϵ P → 1x ϵ P , x1 ϵ P
x' ϵ P,x'' ϵ P → xx'x''ϵ P
Dividing both sides by rt,
Reciprocal just means to flip the fraction around:
6/11
11/6
Answer:
|-30| + |25|
Step-by-step explanation:
The helicopter is 25 ft above the ledge. The stunt actor is 30 below the edge. The distance from the helicopter to the stunt actor is the sum of the two distances, 25 + 30 = 55 ft. The correct expression must equal 55.
A. |-30| + |25| = 30 + 25 = 55
B. -30 - 25 = -55
C. -30 + 25 = -5
D. |-30| - |25| = 30 - 25 = 5
The correct expression is |-30| + |25| since it it the only expression that equals 55.
Hello,
4+0j=4(cos 0+j*sin 0)
3+4j=√5(cos 53.1301...°+j*sin 53.130102...)
2-2j=2√2(cos 45°-j*sin 45°)
