You have to be a bit more specific than that
"He starts both trains at the same time. Train A returns to its starting point every 12 seconds and Train B returns to its starting point every 9 seconds". Basically, what you need to do is find the least common multiple. The least common multiple of 12 and 9 is 36, so the least amount of time, in seconds, that both trains will arrive at the starting points at the same time is 36 seconds.
Answer:
initial value is 21
Step-by-step explanation:
y=mx+b
6= -3(5) +b
b=21
Answer:
2,380
Step-by-step explanation:
