1 stick of butter :))))))))))))))
It is verg important because once diving "The length of one cathetus in a right triangle with equal catheti is the squareroot of half of the squared hypotenuse. And yeah
Let point (x, y) be any point on the graph, than the distance between (x, y) and the focus (3, 6) is sqrt((x - 3)^2 + (y - 6)^2) and the distance between (x, y) and the directrix, y = 4 is |y - 4|
Thus sqrt((x - 3)^2 + (y - 6)^2) = |y - 4|
(x - 3)^2 + (y - 6)^2 = (y - 4)^2
x^2 - 6x + 9 + y^2 - 12y + 36 = y^2 - 8y + 16
x^2 - 6x + 29 = -8y + 12y = 4y
(x - 3)^2 + 20 = 4y
y = 1/4(x - 3)^2 + 5
Required answer is f(x) = one fourth (x - 3)^2 + 5
You just need to multiply 9 1/2 by 11 3/4. simplify these into decimals: 9.5 and 11.75
Then do 9.5*11.75=111.625
