The real solutions of f(x) = 0 is; x = -8, 0 and 4
<h3>How to find the roots of a polynomial graph?</h3>
When talking about real solutions of a polynomial, we are simply referring to the values of x that make the polynomial f(x) = 0.
Now, in a polynomial graph as attached, the real solutions are the roots and they are the values of x where the curve crosses the x-axis.
From the given graph, the real solutions are at x = -8, 0 and 4
Thus, we conclude that the real solutions of f(x) = 0 is; x = -8, 0 and 4
Read more about Polynomial roots graph at; brainly.com/question/14625910
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Answer:
The point of intersection with the x axis are (-2,0) and (8,0)
Step-by-step explanation:
given circle equation x²+y² = 25
x² + y² = r²
r is the radius.
✓(25) = 5
given the center is at (3,0) and radius of 5
(3+5,0) and (3-5,0)
(8,0) and (-2,0)
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Answer:
In basicallity if a question such as this pops up, the correct way to go would first be to graph this. y=x-4 would be equivalent to x=4.
My paper work is below:
y = x - 4
0 = x - 4
-x = -4
x = 4
Hope this helped..
Answer:
8 seconds.
Step-by-step explanation:
To solve this question, we need to find the time, 
, when 
, that is, when the height of the object above the ground is 0 feet.
Substituting 
feet per second and gives the quadratic:
Since 128 is divisible by 16, it can be reduced to 
.
We must now solve for .
We can easily see that one answer to the equation is 0,
(we need not concern ourselves with the 16 outside of the parenthesis as in the equation above, since 16 multiplied by 0 is 0). However this is the time the object is released into the air.
The second answer, 
is also easy to see by inspection:
.
Therefore the object lands 8 seconds after it is thrown.
