Step-by-step answer:
We are looking at the coefficient of the 22nd term of (x+y)^25.
Following the sequence, first term is x^0y^25, second term is x^1y^24, third term is x^2y^23...and so on, 22nd term is x^21y^4.
The twenty-second term of (x+y)^25 is given by the binomial theorem as
( 25!/(21!4!) ) x^21*y^4
=25*24*23*22/4! x^21y^4
= 12650 x^21 y^4
The coefficient required is therefore 12650, for a binomial with unit valued coefficients.
For other binomials, substitute the values for x and y and expand accordingly.
Question would have been more clearly stated if the actual binomial was given, as commented above.
Answer:
12 x 3 = 36 + 33
Step-by-step explanation:
sorry if it's wrong but the answer to the equation i put out would be 69
To find slope intercept form first do rise over run
rise 4 run 3
then find where it crosses the x-intercept to get
y=4/3x-3
2X^2+4X-8-X^2+6X-4
X^2+4X-8+6X-4
X^2+10X-12
The point A is located in quadrant II
The coordinate of the origin is always (0,0)
