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Delvig [45]
4 years ago
11

How do nematocysts capture prey?

Biology
1 answer:
katovenus [111]4 years ago
3 0

Answer:

hm?..but The main function of the nematocyst is prey capture..

but,i do not know what you mean by that.

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How has the development of a pine and then a hardwood forest affected populations of shrubs?
kirill115 [55]

Answer:

Yes, shrubs are affected.

Explanation:

The development of a pine and then a hardwood forest affected populations of shrubs because pine and hardwood trees are higher in length than shrubs so the shrubs did not gain sunlight and also all the nutrients present in the soil is extracted by the pine and hardwood trees. The shrubs present below the pine and hardwood trees slowly removes from that environment due to unavailability of sunlight and nutrients.

3 0
3 years ago
Which food chain represent one way that energy my flow through this ecosystem?
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its a metal chain not a food chain, (steel to be more specific)

Explanation:

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What type of circulatory stay do humans have
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While humans, as well as other vertebrates, have a closed blood circulatory system (meaning that the blood never leaves the network of arteries, veins and capillaries), some invertebrate groups have an open circulatory system containing a heart but limited blood vessels.

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Hello can someone help me please and thank:)
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B- J, L, K

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7 0
2 years ago
In trout, Gene A affects body color and yellow color (allele a) is recessive to red. In a particular river system you find that
hjlf

Answer:

The frequency of the dominant A allele is 0,4 or 40%.

Explanation:

In this population, we have:

- "A" red body color Dominant

- "a" yellow doy color Recessive

So, individuals AA and Aa will be red and trouts aa will be yellow.  In this case, 64% of the fish are red, so they are AA or Aa.

If the population is in Hardy-Weinberg equilibrium the following will be true:

p^{2}+2pq+q^{2}=1

Where:

p^{2}=frequency of AA

2pq= frequency of Aa

q^{2}=frequency of aa

It is known that 64% of population is red, in other words:

p^{2}+2pq=0,64

Or AA+Aa=0,64

So, it is possible to find the value of q^{2} (aa):

p^{2}+2pq+q^{2}=1

(0,64)+q^{2}=1

q^{2}=1-0,64q^{2}=0,36

Now, there are two alleles in this population, therefore their frequencies will be:

p+q=1

So, from q^{2} it is possible to find q and p:

q=\sqrt{q^{2} }

q=\sqrt{0,36}

q=0,6

And:

p+q=1\\p=1-q\\p=1-0,6\\p=0,4

7 0
3 years ago
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