1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dimas [21]
4 years ago
13

Plz help me answer my question

Mathematics
1 answer:
frosja888 [35]4 years ago
6 0
Each triangle is 1/2* b*h
There are 4 triangles so:
4(1/2)*3*5 + 9
30 + 9 = 39ft^2
You might be interested in
Find the measure of an exterior angle of a regular polygon with 9 sides
Contact [7]

Answer: 40°

Step-by-step explanation: The formula for calculating the size of an exterior angle is: exterior angle of a polygon = 360 ÷ number of sides. So it's 360°÷9=40°

3 0
3 years ago
SOLVE <br><br> 2b-5/ b-2 -2 = 3/ b+2
Colt1911 [192]
The answer should be, b = 1
7 0
3 years ago
What is fifteen lots of sixteen?
Brilliant_brown [7]

Answer:

240

Step-by-step explanation:

fifteen lots of sixteen = 15x16

15x16=240

4 0
2 years ago
Lim x-0 3x²/(1-cos5x)
mylen [45]

The limit is presented in the following undefined form:

\displaystyle \lim_{x\to 0}\dfrac{3x^2}{1-\cos(5x)} \to \dfrac{3\cdot 0^2}{1-\cos(5\cdot 0)} = \dfrac{0}{0}

In cases like this, we can use de l'Hospital rule, which states that this limit, if it exists, is the same as the limit of the derivatives of numerator and denominator.

So, we switch

\dfrac{f(x)}{g(x)}\to\dfrac{f'(x)}{g'(x)}

The derivative of the numerator is

\dfrac{d}{dx} 3x^2 = 6x

Whereas the derivative of the denominator is

\dfrac{d}{dx} (1-\cos(5x)) = 5\sin(5x)

So, the new limit is

\displaystyle \lim_{x\to 0}\dfrac{6x}{5\sin(5x)} \to \dfrac{6\cdot 0}{5\cdot 0} = \dfrac{0}{0}

So, it would seem that we didn't solve anything, but indeed we have! Recall the limit

\displaystyle \lim_{x\to 0} \dfrac{ax}{\sin(bx)} = \dfrac{a}{b}

to conclude that the limit converges to \dfrac{6}{25} [/tex]

4 0
4 years ago
Read 2 more answers
The length of the base of a triangle is twice its height. if the area of the triangle is 196 square​ kilometers, find the height
NISA [10]
Area = 1/2 x base x height

Let the height be x.
Height = x
Base = 2x

Area of triangle = 1/2 x base x  heght

Plug base and height into the variables:
(1/2)(2x)(x) = 196

Combine like terms:
x² = 196

Square root both sides:
x = 14

Find Base and height:
Base = x = 14 km
Height = 2x = 2(14) = 28 km

Answer: Height = 28km
4 0
4 years ago
Read 2 more answers
Other questions:
  • One cellular phone carrier charges 26.50 a month plus .15cents a minute. Another carrier charges 14.50 a month plus .25 cents a
    12·2 answers
  • How do u solve this its pre-algebra 4x – 5y = 20
    15·2 answers
  • Please help i need to know this answer ASAP
    14·1 answer
  • Choose all the factors of 12. (Check all that apply.)
    14·2 answers
  • ( NO LINKS ) If x=7, is this equation true? 7 + 9x &gt; 73 *<br><br> A. Yes<br> B. No
    5·1 answer
  • I really need help with this question I’m taking a test it’s urgent !!
    10·1 answer
  • A rectangle has a length of (3y + 2) centimeters and a width of y centimeters. If the perimeter is 44 centimeters, what is the w
    13·1 answer
  • Please help! Answer as many as possible! ​
    11·1 answer
  • What is -3 increased by -9
    10·2 answers
  • Solve the radical equation. Be sure to check all solutions to eliminate extraneous solutions.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!