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Ilya [14]
3 years ago
9

Debi walks laps around the mall for exercise during the winter months. The table represents the number of steps recorded on her

meter as she walks laps around the mall one day. Which statement is true about the graph of the line representing Debi’s data?
a. Debi walks 1,875 steps per lap around the mall.
b. One lap around the mall is equal to about 2,425 steps.
c. One lap around the mall is equal to 4,300 steps.
d. Debi walks 6,175 steps per lap around the mall.

Laps / Steps
0 / 1,875
1 / 4,300
2 / 6,725
3 / 9,150
4 / 11,575
Mathematics
2 answers:
MariettaO [177]3 years ago
5 0

Answer:

<em>The correct option will be:   b. One lap around the mall is equal to about 2,425 steps.</em>

Step-by-step explanation:

Here, we will just find <u>the slope of the line representing Debi’s data</u>. For that, we will take any two data from the table in form of point like (x,y)

Lets take two points as  (0, 1875) and  (2, 6725)

<u>Formula for finding the slope</u> is:  m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}} , where (x_{1}, y_{1}) and (x_{2}, y_{2}) are two given points.

Here,  x_{1}= 0 , y_{1}= 1875 , x_{2}=2 , y_{2}=6725

So, plugging these values into the above formula, we will get......

m= \frac{6725-1875}{2-0}=\frac{4850}{2}=2425

That means, one lap around the mall is equal to about 2,425 steps.

coldgirl [10]3 years ago
4 0

Answer:

One lap around the mall is equal to about 2,425 steps.

Step-by-step explanation:

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Standard form of a point that goes through-2,4 and the slope is -1/7
lesantik [10]

<u>Answer:</u>

Standard form of a line passing through (-2, 4) and having slope of  -1/7 is x + 7y = 26

<u>Solution:</u>

Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7

Standard form of line passing through point ( a , b ) and having slope m is given by

(y – b) = m ( x – a)   --------(1)

In our case given point is ( -2 , 4 ) and slope is -1/7 that means

a = -2 , b = 4 , m = -(1/7)

On substituting given value of a , b and m is equation (1) we get

(y-4)=\left(-\frac{1}{7}\right)(x-(-2))

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=> 7( y - 4 ) = -x – 2

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Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26

8 0
3 years ago
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RSB [31]

Answer:

hmmmmm

Step-by-step explanation:

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3 years ago
Can anyone help me ???
lana [24]
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8 0
3 years ago
Read 2 more answers
What are the zeros of the polynomial function y=2x^3-7x^2+2x+3?
zlopas [31]

y = 2 {x}^{3}  - 7 {x}^{2}  + 2x + 3

By inspection 1 is a root of y ,
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\dfrac{2 {x}^{3} - 7 {x}^{2}  + 2x + 3 }{x - 1}  = 2 {x}^{2}  - 5x - 3 \\  \\ 2 {x}^{2}  - 5x - 3 = (2x + 1)(x - 3)

Hence , the 2 other roots are -1/2 and 3 , and the above graphs confirms the same.

Hope it helps you :)

7 0
3 years ago
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