16/5 is roughly equal to 3.2. Is that what your are asking?
Answer:
a is the answer
Step-by-step explanation:
i got it right
Answer:

Step-by-step explanation:


- In order to combine these two equations, an idea you need to keep in mind is finding a way of setting these equations as equal to each other. I saw that each equation shared a common value,
. In this case, we need to isolate
in the first equation so that both equations
.



- With this, we now know that both
and
are equal to
, so we can set them equal to each other.



- Reply to this if anything I'm saying or doing is confusing in any way, or if you find a mistake. :) Solve for
.







- Hopefully this answer is correct AND makes sense in terms of how I achieved it. Again, reply to this with any questions or mistakes I made and I'll do my best to answer or fix them.
We have to check which of PEMDAS rules can be applied in this case. We have only ADDITION. In this case we can observe that addition is:
1. Associative

2. Commutative

3. has Additive property
Answer:
-75
Step-by-step explanation:
WIthdrew = Negative
-33 - 42 = -75