suppose a triangle has two sides of length 2 and 3 and that the angle between these two sides is 60. what is the length of the t
hird side of the triangle
2 answers:
Answer:
√7 ≈ 2.646
Step-by-step explanation:
The law of cosines is applicable. It tells you ...
c² = a² + b² - 2ab·cos(C) . . . . . where a, b, c are triangle side lengths, and angle C is opposite side c.
Filling in the given information, you have ...
c² = 2² + 3² - 2·2·3·cos(60°) = 4 + 9 - 12·(1/2) = 7
c = √7 ≈ 2.646
The length of the third side is √7, about 2.646 units.
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Answer:
Length = 50 units
width = 35 units
Step-by-step explanation:
Let A, B, C and D be the corner of the pools.
Given:
The points of the corners are.
We need to find the dimension of the pools.
Solution:
Using distance formula of the two points.
----------(1)
For point AB
Substitute points A(30, 25) and B(30, 25) in above equation.
AB = 50 units
Similarly for point BC
Substitute points B(-20, 25) and C(30, -10) in equation 1.
BC = 35 units
Similarly for point DC
Substitute points D(-20, -10) and C(30, -10) in equation 1.
DC = 50 units
Similarly for segment AD
Substitute points A(-20, 25) and D(-20, -10) in equation 1.
AD = 35 units
Therefore, the dimension of the rectangular swimming pool are.
Length = 50 units
width = 35 units