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2 years ago

A map has a scale of 1/2 inch = 20 miles.

Mathematics

1 answer:

dangina [55]2 years ago

4 0

Answer:

70*20=1400/2= 700. that's all

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Simplify the expression. 8x^-10 y^'6 -2x^2y^-8 Write your answer without negative exponents.

sergij07 [2.7K]

Answer:

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}$

Step-by-step explanation:

Given

$8x^{-10}y^6 - 2x^2y^{-8}$

Required

Simplify

Rewrite as:

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6}{x^{10}} - \frac{2x^2}{y^8}$

Take LCM

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6*y^8 - 2x^2 * x^{10}}{x^{10}y^8}$

Apply law of indices

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}$

8 0

2 years ago

Express the system as AX = B; then solve using matrix inverses

Wittaler [7]

Answer with explanation:

1. The given equations are

3x -5 y=2

-x+2 y= 0

⇒The matrix in the form of , AX=B, is

$A=\left[\begin{array}{cc}3&-5\\-1&2\end{array}\right] ,\\\\ X=\left[\begin{array}{c}x&y\end{array}\right],\\\\B=\left[\begin{array}{c}2&0\end{array}\right]$

$\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B$

Adj.A=Transpose of cofactor of Matrix A

$Adj.A=\left[\begin{array}{cc}2&1\\5&3\end{array}\right] ,\\\\ |A|=6-5\\\\|A|=1\\\\\left[\begin{array}{c}x&y\end{array}\right]=\left[\begin{array}{cc}2&5\\1&3\end{array}\right] \times \left[\begin{array}{c}2&0\end{array}\right]\\\\x=4, y=2$

The given equations are

x+y-z=2

x+z=7

2 x +y+z=13

⇒The matrix in the form of , AX=B, is

$A=\left[\begin{array}{ccc}1&1&-1\\1&0&1\\2&1&1\end{array}\right]\\\\ X=\left[\begin{array}{ccc}x\\y\\z\end{array}\right]\\\\B= \left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B\\\\a_{11}=-1,a_{12}=1,a_{13}=1,a_{21}=-2,a_{22}=3,a_{23}=1,a_{31}=1,a_{32}=-2,a_{33}=-1\\\\|A|=1\times(0-1)-1\times(1-2)-1\times(1-0)\\\\=-1+1-1\\\\|A|=-1\\\\Adj.A=\left[\begin{array}{ccc}-1&-2&1\\1&3&-2\\1&1&-1\end{array}\right]$

$\frac{Adj.A}{|A|}=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\\\\X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\times\left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\x=3,y=3,z=4$

7 0

3 years ago

Mei is making fruit punch.

sp2606 [1]

Answer:

16.2p (If lemonade is .75p, if not substitute in the equation below)

Step-by-step explanation:

In 4 liters, there would be 3 liters of lemonade and 1 liter in juice.

I am assuming 75p is meant to be .75p

So 4 liters costs: (1 x 1.8) + (3 x .75) = 4.05

We need 16 so: 4.05 x 4 = 16.2

6 0

2 years ago

How do we find the area of a strange shape? Has six end points so it can become 4 triangles.

Sati [7]

In order to find the area for a strange shape, you divide it up into simpler figures. In this case, you already know that it can be divided into 4 triangles, so find the area of each triangle and add them up. Hope this helped!

6 0

3 years ago

Read 2 more answers

Sum of two numbers is -17. Their difference is 41. Find the numbers

wel

Answer:

$Suppose~the~two~numbers~are~x~and~y.\\From~the~first~condition,\\x+y=-17...........(1)\\From~the~second~condition,\\x-y=41.............(2)\\Adding~eq^n(1)~and~eq^n(2),~we~get,\\x+y+x-y=-17+41\\or, 2x = 24\\or, x=12\\Substituting~x=12~in~eq^n(2),\\y = -17-x = -17-12 = -29$

$So,~the~two~numbers~are~12~and~-29.$

3 0

2 years ago