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2 years ago

3. The x-intercept of a line is -5 and the y-intercept is -2. What is the equation of the line?

Mathematics

1 answer:

alexira [117]2 years ago

4 0

Answer:

1)D

2)D

3)A

Step-by-step explanation:

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21×9=9×21 what property is used

kvv77 [185]

Hello There =)

Commutative property is used. The commutative property states that two numbers can be multiplied in either order.

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2 years ago

Plot the ordered paired (4,-5) state which quadrant or on which axis the point lies

Rudiy27

Answer:

The point is in the 4th quadrant.

Explanation:

Given the ordered pair(4, -5), we have that x = 4 and y = -5. Plotting this point, we'll have;

Note that quadrants are labelled in an anti-clockwise direction with the top right portion of the graph as the 1st quadrant. Looking at the plotted point, we can see that it i in the 4th quadrant.

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Can someone please help me with this

timofeeve [1]

Answer:

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Step-by-step explanation:

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2 years ago

Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with

skad [1K]

Parameterize S by the vector function

$\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle$

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

$\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle$

The integral of the field over S is then

$\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv$

$\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv$

$\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}$

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1 year ago