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Paha777 [63]
3 years ago
12

3-x>2 or 4x+2> 10 what is the graph of the solution to the following compound inequality

Mathematics
1 answer:
mars1129 [50]3 years ago
6 0

Answer:

x<1 is the answer

Step-by-step explanation:

3-x>2

-x>2-3

-x>-1

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Can someone help with this please?
sleet_krkn [62]

Answer:

y = x - 3

Step-by-step explanation:

From the table attached,

Scatter plot given in the graph is correct.

Let the equation of the line passing from a point (x', y') is,

y - y' = m(x - x')

m = slope

Slope of the line passing through two points (x_2,y_2) and (x_1,y_1) is given by,

m = \frac{y_2-y_1}{x_2-x_1}

Therefore, slope of the line passing through the points (11, 8) and (12, 9) will be,

m = \frac{(9-8)}{(12-11)} =1

Therefore, equation of the line passing through (11, 8) will be,

y - 8 = 1(x - 11)

y = x - 11 + 8

y = x - 3

7 0
3 years ago
El reloj de Nuestra Basílica de Chiquinquirá señala cada hora con igual número de campanadas. Para indicar las 6 a.M. Tocó 6 vec
GenaCL600 [577]

Answer:

El reloj de Nuestra Basílica de Chiquinquirá empleará 20 segundos para indicar las 8 a.m.

Step-by-step explanation:

De acuerdo a la información proporcionada, sabes que el reloj de Nuestra Basílica de Chiquinquirá señala cada hora con igual número de campanadas, por lo que a las 8 a.m. tocará 8 campanadas y puedes usar una regla de tres para encontrar cuantos segundos empleará en hacerlo dado que conoces que las 6 campanadas se demoran 15 segundos:

6 campanadas → 15 segundos

8 campanadas →         x

x=(8*15)/6

x= 20

De acuerdo a esto, la respuesta es que el reloj de Nuestra Basílica de Chiquinquirá empleará 20 segundos para indicar las 8 a.m.

4 0
3 years ago
Which verb form correctly completes the sentence? Jessica __________ one of her longer gowns to wear. A. choosed B. had chose C.
irina1246 [14]
D. chose

Jessica chose one of her longer gowns to wear.

Chose is an irregular verb.  It comes form the verb choose, which means to select. The conjugation of choose is chose and chose is a past simple verb.


5 0
3 years ago
Read 2 more answers
On the packaging for a triangular sail, the edge measurements for the sail are listed as 7 ft × 15 ft × 17 ft. Without unfurling
ASHA 777 [7]

Answer:

Shape of Triangular sail is Obtuse Angled Triangle.

Step-by-step explanation:

The triangle is obtuse since the sum of the squares of 2 sides are greater than the square of the third side. (Converse Pythagorean theorem) Hope this helps!

Given: Length of sides of triangular sail = 7 ft , 15 ft , 7 ft

To find: Shape of Sail .i.e., shape of triangle

We use a result which states that

if a , b  , c are sides of triangle where c is greater then a & b.

now, if c² < a² + b² then triangle is Acute angled

if c² = a² + b² then triangle is Right angled

if c² > a² + b² then triangle is Obtuse angled

here a = 7 , b = 7 &  c = 15

c² = 15² = 225

a² + b² = 7² + 7² = 49 + 49 = 98

since, c² > a² + b²

⇒ Triangle must be Obtuse Angled.

Therefore, Shape of Triangular sail is Obtuse Angled Triangle.

7 0
3 years ago
Read 2 more answers
Determine formula of the nth term 2, 6, 12 20 30,42​
nalin [4]

Check the forward differences of the sequence.

If \{a_n\} = \{2,6,12,20,30,42,\ldots\}, then let \{b_n\} be the sequence of first-order differences of \{a_n\}. That is, for n ≥ 1,

b_n = a_{n+1} - a_n

so that \{b_n\} = \{4, 6, 8, 10, 12, \ldots\}.

Let \{c_n\} be the sequence of differences of \{b_n\},

c_n = b_{n+1} - b_n

and we see that this is a constant sequence, \{c_n\} = \{2, 2, 2, 2, \ldots\}. In other words, \{b_n\} is an arithmetic sequence with common difference between terms of 2. That is,

2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2

and we can solve for b_n in terms of b_1=4:

b_{n+1} = b_n + 2

b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2

b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2

and so on down to

b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)

We solve for a_n in the same way.

2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)

Then

a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)

a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))

a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))

and so on down to

a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2

\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}

6 0
2 years ago
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