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3 years ago

3-x>2 or 4x+2> 10 what is the graph of the solution to the following compound inequality

Mathematics

1 answer:

mars1129 [50]3 years ago

6 0

Answer:

x<1 is the answer

Step-by-step explanation:

3-x>2

-x>2-3

-x>-1

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Use the fact that the mean of a geometric distribution is μ= 1 p and the variance is σ2= q p2. A daily number lottery chooses th

butalik [34]

Answer:

a). The mean = 1000

The variance = 999,000

The standard deviation = 999.4999

b). 1000 times , loss

Step-by-step explanation:

The mean of geometric distribution is given as , $\mu = \frac{1}{p}$

And the variance is given by, $\sigma ^2=\frac{q}{p^2}$

Given : $p=\frac{1}{1000}$

= 0.001

The formulae of mean and variance are :

$\mu = \frac{1}{p}$

$\sigma ^2=\frac{q}{p^2}$

$\sigma ^2=\frac{1-p}{p^2}$

a). Mean = $\mu = \frac{1}{p}$

= $\mu = \frac{1}{0.001}$

= 1000

Variance = $\sigma ^2=\frac{1-p}{p^2}$

= $\sigma ^2=\frac{1-0.001}{0.001^2}$

= 999,000

The standard deviation is determined by the root of the variance.

$\sigma = \sqrt{\sigma^2}$

= $\sqrt{999,000}$ = 999.4999

b). We expect to have play lottery 1000 times to win, because the mean in part (a) is 1000.

When we win the profit is 500 - 1 = 499

When we lose, the profit is -1

Expected value of the mean μ is the summation of a product of each of the possibility x with the probability P(x).

$\mu=\Sigma\ x\ P(x)= 499 \times 0.001+(-1) \times (1-0.001)$

= $ 0.50

Since the answer is negative, we are expected to make a loss.

4 0

2 years ago

Please choose the correct answers !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!

vladimir2022 [97]

The answer is A, C ,B

5 0

2 years ago

7x−1)+(−x−2) pls help

Olegator [25]

Answer:

-7x²-13x+2

Step-by-step explanation:

-7x²-14x+1x+2

5 0

2 years ago

The endpoints of one diagonal of a rhombus are (-7, -2) and (-1, -4). If the coordinates of the 3rd vertex are (-6, -9), what ar

podryga [215]

The coordinates of the 4th vertex of the rhombus are (-2,3)

<h3>How to determine the coordinates of the 4th vertex?</h3>

The diagonals are given as:

(-7, -2) and (-1, -4)

The 3rd vertex is given as: (-6,-9)

Calculate the distance between the vertices of the diagonals and the 3rd vertex using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2}$

So, we have:

$d_1 = \sqrt{(-7 + 6)^2 + (-2 + 9)^2} =\sqrt{50$

$d_2 = \sqrt{(-1 + 6)^2 + (-4 + 9)^2} =\sqrt{50$

Let the 4th vertex be (x,y)

So, we have:

$d_3 = \sqrt{(-7 - x)^2 + (-2 - y)^2} =\sqrt{50$

$d_4 = \sqrt{(-1 - x)^2 + (-4 - y)^2} =\sqrt{50$

Equate d3 and d4

$\sqrt{(-1 - x)^2 + (-4 - y)^2} = \sqrt{(-7 - x)^2 + (-2 - y)^2}$

Take the square of both sides

$(-1 - x)^2 + (-4 - y)^2 = (-7 - x)^2 + (-2 - y)^2$

Expand

$1 + 2x + x^2 + 16 + 8y + y^2 = 49 + 14x + x^2 + 4 + 4y + y^2$

Evaluate the like terms

1 + 2x + 16 + 8y = 49 + 14x + 4 + 4y

Collect like terms

14x - 2x + 4y - 8y = 1 + 16 - 49 - 4

12x - 4y = -36

Divide through by 4

3x - y = -9

Next, we test the options in the above equation

Point (-8,13) means x = -8 and y = 13

So, we have:

3x - y = -9

3(-8) - 13 = -9

-37 = -9 --- this is false

Point (-2, 3) means x = -2 and y = 3

So, we have:

3x - y = -9

3(-2) - 3 = -9

-9 = -9 --- this is true.

Hence, the coordinates of the 4th vertex are (-2,3)