Answer:
The proportion of jugs which receive more than 65 ounces of detergent is 0.0062 or 0.62%
Step-by-step explanation:
Mean amount of detergent = u = 64
Standard deviation =
= 0.4
We need to find the proportion of jugs with over 65 ounces of detergent. Since the population is Normally Distributed and we have the value of population standard deviation, we will use the concept of z-score to solve this problem.
First we will convert 65 to its equivalent z-score, then using the z-table we will desired proportion. The formula to calculate the z-score is:

x = 65 converted to z score will be:

Therefore, the probability of detergent being more than 65 ounces is equivalent to probability of z-score being over 2.5
i.e.
P(X > 65) = P(z > 2.5)
From the z-table and using the property of symmetry:
P(z > 2.5) = 1 - P(z < 2.5)
= 1 - 0.9938
= 0.0062
Therefore,
P(X > 65) = P(z > 2.5) = 0.0062
So, the proportion of jugs which receive more than 65 ounces of detergent is 0.0062 or 0.62%
Whole numbers close to 5 1/8
are 5 and 6
1/8 is less than 1/2
so we should round down
therefore the nearest whole number should be 5
the formula to find the diagonal would be
a^2+b^2=c^2
3^2+4^2= 9+16=25
the square root of 25 is 5
5^2=25
so your diagonal is 5 ft
You just need to foil. 2x times 4x times 2x times 36 times 24 times 4x times 24times 36. then solve.