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3 years ago

How many gallons do you need for every 150 miles

Mathematics

1 answer:

Vaselesa [24]3 years ago

6 0

Answer:

you would use 1.65 gallons every 150 miles

Step-by-step explanation:

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Please help! 15 points! <br><br> Btw, you cannot answer in the file.....that's just a pic.....

olchik [2.2K]

You can find the value of x using the trigonometric function of cosine.

cos x = adj/hyp
cos 49 = x/55
55(cos 49) = x
36.083 = x

Hope I am right :)

8 0

3 years ago

What are three rational numbers between -1 and -2

MArishka [77]

well, rational = fractional, namely something you can write as a fraction, well, anything between -1 and -2 is just less than -1 so

$\bf \boxed{-2}\dotfill \stackrel{-1-\frac{1}{4}}{-\cfrac{5}{4}}\dotfill\stackrel{-1-\frac{1}{10}}{-\cfrac{11}{10}}\dotfill \stackrel{-1-\frac{1}{99}}{-\cfrac{100}{99}}\dotfill \boxed{-1}$

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2 years ago

.000033 + (5 x 10^-5)<br> Answer in scientific and standard form

qaws [65]

$0.000033 + (5 \times {10}^{ - 5})$

$= 8.3 \times {10}^{ - 5}$

$= 0.000083$

6 0

3 years ago

Which of the following is NOT equivalent to 240/300

Lyrx [107]

Two fractions are said to be equivalent if both the numerator and the numerator of one fraction can be obtained by multiplying or dividing the numerat.or and denominator of the other fraction by a single factor.

Dividing the numerator and denominator of 240/300 by 5 gives 48/60
Dividing the numerator and denominator of 240/300 by 60 gives 4/5
Dividing the numerator and denominator of 240/300 by 10 gives 24/30

Whereas dividing 300 by 2 gives 150 dividing 240 by 2 will not give 122. so 122/150 is not equivalent to 240/300.

7 0

3 years ago

For the function g(x)=3-8(1/4)^2-x

Reika [66]

Using function concepts, it is found that:

a) The y-intercept is y = 2.5.

b) The horizontal asymptote is x = 3.

c) The function is decreasing.

d) The domain is $(-\infty,\infty)$ and the range is $(-\infty,3)$ .
e) The graph is given at the end of the answer.

------------------------------------

The given function is:

$g(x) = 3 - 8\left(\frac{1}{4}\right)^{2-x}$

------------------------------------

Question a:

The y-intercept is g(0), thus:

$g(0) = 3 - 8\left(\frac{1}{4}\right)^{2-0} = 3 - 8\left(\frac{1}{4}\right)^{2} = 3 - \frac{8}{16} = 3 - 0.5 = 2.5$

The y-intercept is y = 2.5.

------------------------------------

Question b:

The horizontal asymptote is the limit of the function when x goes to infinity, if it exists.

$\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2+\infty} = 3 - 8\left(\frac{1}{4}\right)^{\infty} = 3 - 8\frac{1^{\infty}}{4^{\infty}} = 3 -0 = 3$

--------------------------------------------------

$\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2-\infty} = 3 - 8\left(\frac{1}{4}\right)^{-\infty} = 3 - 8\times 4^{\infty} = 3 - \infty = -\infty$

Thus, the horizontal asymptote is x = 3.

--------------------------------------------------

Question c:

The limit of x going to infinity of the function is negative infinity, which means that the function is decreasing.

--------------------------------------------------

Question d:

Exponential function has no restrictions in the domain, so it is all real values, that is $(-\infty,\infty)$ .
From the limits in item c, the range is: $(-\infty,3)$

--------------------------------------------------

The sketching of the graph is given appended at the end of this answer.

A similar problem is given at brainly.com/question/16533631

8 0

2 years ago