<h3><em>A = p(1+r/n)nt
</em></h3><h3><em>A = final amount
</em></h3><h3><em>p = principal = 2000
</em></h3><h3><em>r = interest rate = .04
</em></h3><h3><em>n = # times compounded pet year = 2
</em></h3><h3><em>t = time in years = 7
</em></h3><h3><em> </em></h3><h3><em>A = 2000(1+.04/2)2(7)
</em></h3><h3><em>A = 2000(1.02)14
</em></h3><h3><em>A= 2638.957</em></h3><h3><em>HOPE IT HELPS.....</em></h3>
Domain: 
Range: 
The relation is not a function.
Explanation:
The coordinates
are plotted in the graph. The image of the graph is attached below.
The domain of a relation is the set of all x-values for which the function is well defined. Thus, the domain are 
The range of a relation is the set of all y-values obtained by substituting the values for x in the function. Thus, the range are 
The relation
is not a function since, -4.7 has two different y-values. By definition of function, the function cannot have two different y-values for the same x-value.
V + f - e = 2
e = v + f - 2
Answer:
Q' (12,8) , R'( 24,20) and S' (24,8)
Step-by-step explanation:
Here, we want to get the coordinates of the image after dilating the pre-image by a scale factor of 4
What we have to do here is to multiply each of the coordinate on the pre-image by 4
We have this as;
Q' = (4*3, 2 * 4) = (12,8)
R' = (4*6, 4*5) = (24,20)
s' = (4*6, 4*2) = (24,8)