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viktelen [127]
3 years ago
11

Midpoint of the segment between the points (−5,13) and (6,4)

Mathematics
2 answers:
Leokris [45]3 years ago
6 0

Answer: (0.5,8.5)

Step-by-step explanation:

We need to use the following formula to find the Midpoint "M":

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Given the points (-5,13) and (6,4) can identify that:

x_1=-5\\x_2=6\\\\y_1=13\\y_2=4

The final step is to substitute values into the formula.

Therefore, the midpoint of the segment between the points (-5,13) and (6,4) is:

M=(\frac{-5+6}{2},\frac{13+4}{2})\\\\M=(\frac{1}{2},\frac{17}{2})\\\\M=(0.5,8.5)

N76 [4]3 years ago
6 0

Answer:

(\frac{1}{2},\frac{17}{2})

Step-by-step explanation:

Midpoint formula is

( \frac{x + x_1}{2},\frac{y + y_1}{2})

The given points are,

(-5,13) and (6,4)

( \frac{-5 + 6}{2},\frac{13+4}{2})

( \frac{1}{2},\frac{17}{2})

Hence the midpoint of the segment between (-5,13) and (6,4) is

( \frac{1}{2},\frac{17}{2})

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3 years ago
Graph the given relation or equation and find the domain and range. Then determine whether the relation or equation is a functio
KiRa [710]

Domain: \{3.3,-1.7,-4.7\}

Range: \{5.3,3.3,-2.7\}

The relation is not a function.

Explanation:

The coordinates (3.3,5.3), (-1.7,5.3), (-4.7,3.3), (-4.7,-2.7) are plotted in the graph. The image of the graph is attached below.

The domain of a relation is the set of all x-values for which the function is well defined. Thus, the domain are \{3.3,-1.7,-4.7\}

The range of a relation is the set of all y-values obtained by substituting the values for x in the function. Thus, the range are \{5.3,3.3,-2.7\}

The relation (3.3,5.3), (-1.7,5.3), (-4.7,3.3), (-4.7,-2.7) is not a function since, -4.7 has two different y-values. By definition of function, the function cannot have two different y-values for the same x-value.

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4 years ago
Estimate: 5/7 of 22
mote1985 [20]
It should be about15.75
3 0
3 years ago
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How do you answer this question <br> V+f-e=2 for e
Anna35 [415]
V + f - e = 2
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8 0
4 years ago
The polygon Q(3, 2), R(6,5), S(6, 2)
ycow [4]

Answer:

Q' (12,8) , R'( 24,20) and S' (24,8)

Step-by-step explanation:

Here, we want to get the coordinates of the image after dilating the pre-image by a scale factor of 4

What we have to do here is to multiply each of the coordinate on the pre-image by 4

We have this as;

Q' = (4*3, 2 * 4) = (12,8)

R' = (4*6, 4*5) = (24,20)

s' = (4*6, 4*2) = (24,8)

4 0
3 years ago
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