Pam is an employee at a jewelry kiosk in a mall. If Pam works hard, there is a 75% probability that jewelry profits will equal $

Question

Citrus2011 [14]

3 years ago

6

Pam is an employee at a jewelry kiosk in a mall. If Pam works hard, there is a 75% probability that jewelry profits will equal $

400 a day and a 25% probability that jewelry profits will equal $200 a day. If Pam shirks, there is a 25% probability that jewelry profits will equal $400 a day and a 75% probability that jewelry profits will equal $200 a day. Suppose Pam is paid 50% of the daily jewelry profits. What is Pam’s expected gain from working hard?

Mathematics

1 answer:

Greeley [361] · Answer 1 · 2022-02-23T02:29:35+03:00

Answer:

175$

Step-by-step explanation:

Given that Pam is an employee at a jewelry kiosk in a mall. If Pam works hard, there is a 75% probability that jewelry profits will equal $400 a day and a 25% probability that jewelry profits will equal $200 a day. If Pam shirks, there is a 25% probability that jewelry profits will equal $400 a day and a 75% probability that jewelry profits will equal $200 a day.

Since Pam works hard

expected value of profit for the kiosk = $400(0.75)+200(0.25)\\=350$

From this value, 50% would be given to Pam

Hence expected gain for Pam for working hard

= $0.5(350)\\=175$

175 $