Answer:
1. 6x^2 + 4x - 4y
2. x - 10y.
3. 6x^5
4. 36 a^6 b^8
5. x^2 - 81
6. 9x^2 - 42x + 49
7. 12x^2 +3x - 42
Step-by-step explanation:
1. 3x^2+4x+3x^2-4y
Add the like terms, we get
6x^2 + 4x - 4y
2. (5x-2y)-(4x+8y)
Now distribute the negative sign, we get
5x - 2y -4x -8y
Simplify the like terms, we get
x - 10y.
3. 3x^3(2x)^2
Multiply the numbers and simplify the variables
6x^(3 +2)
6x^5
4. (-6a^3b^4)^2
Now bring the power 2 inside the parenthesis.
-6^2 a^6 b^8
= 36a^6b^8
5. (x+9) (x-9)
x^2 + 9x -9x - 81
x^2 - 81
6. (3x-7)^2
(3x - 7)(3x - 7)
9x^2 - 21x -21x + 49
9x^2 - 42x + 49
7. (3x+6) (4x-7)
12x^2 + 24x -21x - 42
12x^2 +3x - 42
Thank you.
Y varies directly with x" means y = constant * x or y = kx ----- (1)1. when x = -1/2, y = 2Put it in (1):2 = k * (-1/2)multiply by 2:4 = k * (-1)4 = -kk = -4y = -4x
"find the value of y when x= -0.3"y = -4x = (-4) * (-0.3) = 1.2
So for each problem, start with y = kxThey give you one x and one y value.Put it in y = kx and find k.Then put x = -0.3 and find y.
5x + 8 = 4
5x = -4
x = -4/5
3(-4/5) = -2.4
Solution: 3x = -2.4
Let the age be x.
Given,





Hence, x = -2 or 25.
Since, the age of the teacher cannot be in negative, the age of the teacher is
25 years.