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Citrus2011 [14]
3 years ago
6

Pam is an employee at a jewelry kiosk in a mall. If Pam works hard, there is a 75% probability that jewelry profits will equal $

400 a day and a 25% probability that jewelry profits will equal $200 a day. If Pam shirks, there is a 25% probability that jewelry profits will equal $400 a day and a 75% probability that jewelry profits will equal $200 a day. Suppose Pam is paid 50% of the daily jewelry profits. What is Pam’s expected gain from working hard?
Mathematics
1 answer:
Greeley [361]3 years ago
3 0

Answer:

175$

Step-by-step explanation:

Given that Pam  is an employee at a jewelry kiosk in a mall. If Pam works hard, there is a 75% probability that jewelry profits will equal $400 a day and a 25% probability that jewelry profits will equal $200 a day. If Pam shirks, there is a 25% probability that jewelry profits will equal $400 a day and a 75% probability that jewelry profits will equal $200 a day.

Since Pam works hard

expected value of profit for the kiosk = 400(0.75)+200(0.25)\\=350

From this value, 50% would be given to Pam

Hence expected gain for Pam for working hard

= 0.5(350)\\=175

175 $

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