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worty [1.4K]
4 years ago
12

Can someone plz help me as soon as possible plz someone help me ASAP

Mathematics
1 answer:
Ghella [55]4 years ago
4 0

Answer:

4 pages per hour

Step-by-step explanation:

We want to find the pages per hour

Take the pages and divide by the hours

7

-----

1 3/4

Change to an improper fraction

7

-----

7/4

Multiply the top and bottom by 4/7

7*4/7

-----

7/4 *4/7

4

-----

1

He can write 4 pages per hour

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Which one of the following English phrases translates to this algebraic expression? 3n - 15
zhenek [66]

Answer:

C

Step-by-step explanation:

It is stating that it is 15 less(-15) than the Product of 3 and some number(3n)

5 0
3 years ago
4. Entomologists introduce 20 of one
Lina20 [59]

Answer:

This number can be found using the Rule of 70, which describes the formula dt = 70 / r, where dt is the doubling time, and r is the annual rate of growth.

Step-by-step explanation:

24/6 = 4

20 x 2 = 40 x 2 = 80 x 2 = 160 x 2 = 320

20 ---> 320 in the first day.

Keep doing this equation. Multiply each day's end result by 2 four times for 9 more days.

8 0
4 years ago
What’s the answer? Why? Show the steps on how you go it
sleet_krkn [62]
This is not answer but Photomath is really helpful and it shows you step by step on how to solve it as well
7 0
4 years ago
Please I need the polynomial for this problem, if you don’t know then don’t answer! Wrong answers will be reported
babymother [125]

Answer:

Area = (36π - 12πx + x²π) mm²

Step-by-step explanation:

Given that,

radius of lense = 6mm

Length from outer layer of pupil to lense = x mm

Radius of pupil = 6 - x mm

<h3>Formula to calculate area of pupil</h3><h3> Area = π r²</h3>

<em> where r is radius of pupil</em>

Area = π (6 -x)²

Area = π (6² -2(6)(x) + x²)

Area = π (36 -12x +x²)

Area = (36π - 12πx + x²π) mm²

So, the polynomial in standard form that represent the area of pupil in terms of π =  (36π - 12πx + x²π) mm²

5 0
3 years ago
Y= 3x-1<br> 2x+6=y substitution method
vfiekz [6]

Answer: (7, 20)

Concept:

There are three general ways to solve systems of equations:

  1. Elimination
  2. Substitution
  3. Graphing

Since the question has specific requirements, we are going to use <u>substitution </u>to solve the equations.

Solve:

<u>Given equations</u>

y = 3x - 1

2x + 6 = y

<u>Substitute the y value since both equations has isolated [y]</u>

2x + 6 = 3x - 1

<u>Add 1 on both sides</u>

2x + 6 + 1 = 3x - 1 + 1

2x + 7 = 3x

<u>Subtract 2x on both sides</u>

2x + 7 - 2x = 3x - 2x

\boxed{x=7}

<u>Find the value of y</u>

y = 3x - 1

y = 3(7) - 1

y = 21 - 1

\boxed{y=20}

Hope this helps!! :)

Please let me know if you have any questions

3 0
3 years ago
Read 2 more answers
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