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kari74 [83]
3 years ago
12

the student Council wants to rent a ballroom for the junior prom. the balroom’s rental rate is $1500 for three hours and $125 fo

r each additional half hour. Suppose the student council raises $2125. What is the maximum number of hours for which they can rent the ballroom?
Mathematics
1 answer:
Tomtit [17]3 years ago
4 0
They can rent it for 5 1/2 hours
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Round off 787592799 to the nearest 10​
timama [110]

Answer:

787592800

Step-by-step explanation:

Hi there,

If you round this answer to the nearest tens place, it would be 787592800. Since the 799 is closer to 800 rather than 790, it would round up and change the last three digits of the number instead of the usual two digits.

Hope this answer helps. Cheers.

3 0
2 years ago
19/100 x g/10 help please :0
Rudik [331]

19g/1000 would be the right answer when simplified.

4 0
3 years ago
If it costs $3.50 per square foot, what is the approximate total cost of making this
Leni [432]

Answer:

the right answer would be C

7 0
2 years ago
Read 2 more answers
If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle
stira [4]

Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

6 0
3 years ago
Given the function f(x) = x3 + 2x2 − 3x − 5, what is resulting function when f(x) is shifted to the right 1 unit?
cluponka [151]
When shifted to the right 1 unit it would be:
f(x - 1) = (x - 1)^3 + 2(x - 1)^2 - 3(x - 1) - 5 
<span>= (x^3 - 3x^2 + 3x - 1) + 2(x^2 - 2x + 1) - 3(x - 1) - 5 </span>
<span>= x^3 - 3x^2 + 2x^2 + 3x - 4x - 3x - 1 + 2 + 3 - 5 </span>
<span>= x^3 - x^2 - 4x - 1 
</span>I hope this helps
5 0
3 years ago
Read 2 more answers
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