Answer:
The weight of large and small box are 18.25 kg and 13.25 kg respectively.
Step-by-step explanation:
Let the weight of large and small box are x and y respectively.
It is given that a delivery of 5 large boxes and 3 small boxes has a total weight of 131 kilograms.
.... (1)
A delivery of 2 large boxes and 6 small boxes has a total weight of 116 kilograms.
.... (2)
On solving (1) and (2) using graphing calculator, we get
Therefore the weight of large and small box are 18.25 kg and 13.25 kg respectively.
Answer: 21.375 cm2
Step-by-step explanation:
Area of rectangle = length x width = 3.5 x 4.4 = 15.75 cm2
Area of triangle = 1/2 x base x height = 1/2 x 2.5 x 4.5 = 5.625 cm2
Add rectangle and triangle area = 21.375 cm2
Answer:
x = 36/5
Step-by-step explanation:
Subtract 6 from both sides
x/3+6-2x-6 = -6-6
Simplify
x/3 - 2x = -12
Multiply both sides by 3
x/3 * 3 - 2x * 3 = -12 * 3
Simplify
-5x = -36
Divide both sides by -5
-5x/-5 = -36/-5
Simplify
x = 36/5
Answer:
{x=2,y=2
Step-by-step explanation:
Equation 1:
Multiply both sides of the equation by a coefficient
{ 4(2x-y)=2*4
-5x+4y=-2
Apply Multiplicative Distribution Law
{8x-4y=2*4,-5x+4y=-2
8x-4y+(-5x+4y)=8+(-2)
Remove parentheses
8x-4y-5x+4y=8-2
Cancel one variable
8x-5x=8-2
Combine like terms
3x=8-2
Calculate the sum or difference
3x=6
Divide both sides of the equation by the coefficient of the variable
x=6/3
Calculate the product or quotient
x=2
Equation two:
{-5+4y=-2, x=2
-5*2+4y=-2
Calculate the product or quotient
-10+4y =-2
Reduce the greatest common factor (GCF) on both sides of the equation
-5+2y=-1
Rearrange unknown terms to the left side of the equation
2y=-1+5
Calculate the sum or difference
2y=4
Divide both sides of the equation by the coefficient of the variable
y=4/2
y=2
Hope this helps!!
