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Vsevolod [243]
3 years ago
11

Eight less than the product of 4 and a number is equal to 9.​

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
6 0
Hope this helps with the answer to your question :)

Len [333]3 years ago
5 0

Answer:

4x - 8 = 9

Step-by-step explanation:

Hope this helps! :)

Please choose me! I was first! :) PLS BRAINLIEST I NEED ONE MORE! :(

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I need help with math
Marat540 [252]
The answer is C that’s all I can give to you
6 0
3 years ago
Please help meee! :< An author receives $0.60 for each hardcover book or paperback book that is sold. There were x hardcover
rusak2 [61]
D) 47,000

0.60 (<em>x</em>+38,000)= 51,000
(0.60<em>x</em>)+22,800= 51,000
51,000-22,800= 28,200
28,200÷0.60= 47,000
0.06 (47,000+38,000)= 51,000
28,200+22,800= 51,000
5 0
3 years ago
Please help ASAP!!!!!
ra1l [238]
These tables have infinitely many values, but the simplest ones would be:
a) x|y
    3|5
    6|10
    9|15

b) x|y
    2|1
    4|2
    6|3

Your graph for c would look like the attached picture

7 0
3 years ago
Read 2 more answers
Brent is a researcher for a food company. He is on a team creating a reduced-calorie version of its flagship cracker. The team w
Andre45 [30]

Answer:

Step-by-step explanation:

Hello!

The research team created a cracker with fewer calories. The average content of calories of the new crackers per serving of 6 should be less than 60.

To test it a random sample of 26 samples of the new cracker was taken and the calories per serving were measured.

Then the study variable is

X: calories of a 6 serve sample of the new reduced-calorie version. (cal)

The variable has a normal distribution with a population standard deviation of 0.82 cal.

To test the claim that the new crackers have on average less than 60 calories, the parameter of interest is the population mean (μ) and the hypotheses are:

H₀: μ ≥ 60

H₁: μ < 60

α: 0.01

Since the variable has a normal distribution and the population variance is known, the best statistic to use to conduct the test is a Standard Normal

Z= \frac{(X[bar]-Mu)}{\frac{Sigma}{\sqrt{n}}  } ~N(0;1)

This test is one tailed to the left, wich means that the null hypothesis will be rejected at low levels of the statistic.

Z_{\alpha } = Z_{0.01} = -2.334

If Z ≤ -2.334, the decision is to reject the null hypothesis.

If Z > -2.334, the decision is to not reject the null hypothesis.

Using the data of the sample I've calculated the sample mean.

X[bar]= ∑X/n= 1548.61/26= 59.56 cal

Z_{H_0}= \frac{(59.56-60)}{\frac{0.82}{\sqrt{26} } } = -2.736

The observed Z value is less than the critical value, so the decision is to reject the null hypothesis.

At a level of significance of 1%, you can conclude that the population mean of calories of the samples of new crackers is less than 60 cal.

I hope it helps!

6 0
3 years ago
What is another name for line m?
Ganezh [65]
I’m pretty sure it’s the slope
5 0
3 years ago
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