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2 years ago

FRAME AN EQUATION AND SOLVE IT. NEED HELP ASAP I only have 5 minutes!

Mathematics

1 answer:

lawyer [7]2 years ago

3 0

Answer:

The answer to your question is 125

Step-by-step explanation:

x = 25 X 5= 125.

The required number is 125.

I hope this helps and have a good day!

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Question 2 (1 point)

KIM [24]

Answer:

first week = m miles

second week = 6 miles less than triple the number of miles they ran the

first week.

Triple of the number of miles they ran the first week = 3 * m = 3m

Therefore = 3m - 6

3 0

3 years ago

What is the product?

Lerok [7]

You just have to multiply straight across. Multiply the numerators for the new numerator, and the denominators for the new denominator.
5*3=15
4*8=32
15/32 is the answer (b).

5 0

2 years ago

Read 2 more answers

You are building a shelf that fits in a corner. In the figure, the entire shelf is △XYZ. Each unit in the coordinate plane repre

natima [27]

Complete Question: You are building a shelf that fits in a corner in the figure the entire shelf is XYZ each unit in the coordinate plane represents one inch find the area of the shelf.

Answer:

112.5 units²

Step-by-step explanation:

Area of the shelf = ½*base*height.

The base is the distance between Z(0, 5) and Y(15, 5)

The height is the distance between X(15, 20) and Y(15, 5).

Therefore area of the shelf = ½*ZY*XY

Use the distance formula to find ZY and XY.

Distance between Z(0, 5) and Y(15, 5):

$ZY = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$Z(0, 5) = (x_1, y_1)$

$Y(15, 5) = (x_2, y_2)$

$ZY = \sqrt{(15 - 0)^2 + (5 - 5)^2}$

$AB = \sqrt{(15)^2 + (0)^2}$

$AB = \sqrt{225 + 0} = \sqrt{225}$

$AB = 15$

Distance between X(15, 20) and Y(15, 5):

$XY = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$X(15, 20) = (x_1, y_1)$

$Y(15, 5) = (x_2, y_2)$

$XY = \sqrt{(15 - 15)^2 + (5 - 20)^2}$

$XY = \sqrt{(0)^2 + (-15)^2}$

$XY = \sqrt{0 + 225} = \sqrt{225}$

$XY = 15$

Area of shelf = ½*15*15 = ½*225 = 112.5 units²

4 0

3 years ago

An item is regularly priced at 85$. It is on sale for 80% off the regular price. How much is discounted from the regular price?

laila [671]

$68 is discounted from the regular price.

To find this, you first divide 80% by 100 to get 0.8 (the decimal form of the percentage). Then, simply multiply 0.8 by 85 (or vise verse) to get $68. Since the question is asking for how much is discounted from the regular price, the final answer would be $68.

I hope this helps!

4 0

3 years ago

Please help and explain how

azamat

18, 42, and 27. they were all times by 2

7 0

3 years ago

FRAME AN EQUATION AND SOLVE IT. NEED HELP ASAP I only have 5 minutes!​

FRAME AN EQUATION AND SOLVE IT. NEED HELP ASAP I only have 5 minutes!