Hello from MrBillDoesMath!
Answer:
x = 80/3 ( 26 2/3)
y = 11
Discussion:
Step 1:
-2 + y = 9 => add 2 to both sides
2 + -2 + y = 9 +2 =>
y = 11
Step 2:
Substitute y = 11 (from Step 1) into
3x - 7y = 3 =>
3x - 7(11) = 3 => y = 11 from Step 1
3x - 77 = 3 => add 77 to both sides
3x - 77 + 77 = 3 + 77 =>
3x = 80 =>
x = 80/3
Thank you,
MrB
75390
7 is in the ten thousand place
5 is in the thousand place
3 is in the hundreds place
9 is in the tens place
1 is in the ones place
Answer:
32
Step-by-step explanation:
Answer:
I will use "complete-the-square" approach if thats ok
first 0.5(x - 2)² - 2
second -2(x - 4)² + 8
The probability that a 2 or 3 is rolled at least once is 0.14.
<h3>
Probability of not rolling a 2 or 3 in a single die roll of two dice</h3>
when a six die is rolled once there is 11/12 probability of not rolling 2 or 3.
rolling a six sided die two times, p(2 or 3)' = 11/12
rolling a six sided die four times, p(2 or 3)' = (11/12)² = 121/144
the probability that a 2 or 3 is rolled at least once is calculated as follows;
P = 1 - p(2 or 3)'
P = 1 - 121/144
P = 20/144
P = 0.14
Thus, the probability that a 2 or 3 is rolled at least once is 0.14.
Learn more about probability here: brainly.com/question/24756209
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