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Nadusha1986 [10]
3 years ago
14

help solve this problem Based on a​ poll, 62​% of Internet users are more careful about personal information when using a public

​ Wi-Fi hotspot. What is the probability that among four randomly selected Internet​ users, at least one is more careful about personal information when using a public​ Wi-Fi hotspot? How is the result affected by the additional information that the survey subjects volunteered to​ respond?
Mathematics
1 answer:
erma4kov [3.2K]3 years ago
6 0

Answer

The probability that among four randomly selected Internet​ users, at least one is more careful about personal information when using a public​ Wi-Fi hotspot is 0.979.

Step-by-step explanation:

Since  62​% of Internet users are more careful about personal information when using a public​ Wi-Fi hotspot.

Therefore, the Probability of 62​% of Internet users are more careful about personal information when using a public​ Wi-Fi hotspot is, p=0.62.

We have to find the probability that at least one user is more careful about personal information when using wi-fi hotspot.

Probability of internet users are not more careful about personal information when using a public wi-fi hotspot, i.e q=1-p

q=1-0.62=0.38

Use Binomial Distribution, i.e,  P\left ( X \right )=^nC_xp^xq^\left ( n-x \right )

p=0.62, q=0.38, n=4.

Required Probability  P\left ( X\geq 1 \right )=P\left ( X=1 \right )+P\left ( X=2 \right )+P\left ( X=3 \right )+P\left ( X=4 \right )

or

P\left ( X\geq 1 \right )=1-P\left ( X=0 \right )

                                          =1-^4C_0p^0q^\left ( 4-0 \right )

                                          =1-4\cdot1\cdot q^\left ( 4-0 \right )

                                         =1-4\cdot \left ( 0.38 \right )^4

                                         =1-0.02085136=0.97914864

Therefore, the probability that at least one users more careful about personal information when using wi-fi hotspot, i.e 0.979(approx).

RESULT:

<u>The result should not be impacted by this because volunteers are likely to have the most relevant responds.</u>



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Step-by-step explanation:

The specification for a plastic handle calls for a length of 6.0 inches ± .2 inches. The standard deviation of the process is estimated to be 0.05 inches. What are the upper and lower specification limits for this product? The process is known to operate at a mean thickness of 6.1 inches. What is the Cp and Cpk for this process?   Is this process capable of producing the desired part?

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