5600.014
= 5000 + 600 + 0.010 + 0.004
i am a mathematics teacher. if anything to ask please pm me
6x + x + x - 5 - 2 = 8 + 2x + x
combine like terms
8x -7 = 8 +3x
subtract 3x from each side
5x -7 = 8
add 7 to each side
5x = 15
divide by 5
x=3
Answer: 8x -7 = 8 +3x
x=3
The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
Learn more about TRIANGLE here brainly.com/question/2217700
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Answer:
For tingle #1
We can find angle C using the triangle sum theorem: the three interior angles of any triangle add up to 180 degrees. Since we know the measures of angles A and B, we can find C.
We cannot find any of the sides. Since there is noting to show us size, there is simply just not enough information; we need at least one side to use the rule of sines and find the other ones. Also, since there is nothing showing us size, each side can have more than one value.
For triangle #2
In this one, we can find everything and there is one one value for each.
- We can find side c
Since we have a right triangle, we can find side c using the Pythagorean theorem
- We can find angle C using the cosine trig identity
- Now we can find angle A using the triangle sum theorem
For triangle #3
Again, we can find everything and there is one one value for each.
- We can find angle A using the triangle sum theorem
- We can find side a using the tangent trig identity
- Now we can find side b using the Pythagorean theorem
8[2] + 6[2] = c[2]
64 + 36 = c[2]
100 = c[2]
c = 10
8 + 6 + 10 = 24 units