All categories

3 years ago

How is the equation Y= 2X similar to the equation Y = 2X +3. how is it different

Mathematics

2 answers:

Svetlanka [38]3 years ago

8 0

Answer:

2x in common (slope)

Step-by-step explanation:

similar because they both have a slope of 2

different because the 2nd equation has a y intercept of 3

Alexxx [7]3 years ago

4 0

Answer:

Step-by-step explanion:

In slope intercept form (y=mx+b) the "mx" is the slope of the line and the "b" is where the line starts out on the y axis.

So since these lines both have the same slop they are parellel to eachother (like train tracks and will never cross) Hope this helps m8 :)

You might be interested in

On a number line, A is at -2 and B is at 4. What is the coordinate of C, which is 2/3

STatiana [176]

Answer:

Step-by-step explanation:

The distances have the ratio:

(C -A) = (2/3)(B -A)

C = (2/3)B +(1/3)A . . . . . add A

C = (2B +A)/3 . . . . . . . . combine terms

C = (2(4) +(-2))/3 = 6/3 = 2

The coordinate of C is 2.

7 0

2 years ago

Line h contains the points (3,0) and (0,4). which point lies on a line that is perpendicular to line h and passes through point

Iteru [2.4K]

(3,0)(0,4)
slope = (4 - 0) / (0 - 3) = -4/3
A perpendicular line will have a negative reciprocal slope. So our perpendicular line has a slope of 3/4

y = mx + b
slope(m) = 3/4
(-6,-5)....x = -6 and y = -5
now sub into the formula and find b, the y int
-5 = 3/4(-6) + b
-5 = -18/4 + b
-5 + 18/4 = b
-20/4 + 18/4 = b
-2/4 = b
so ur perpendicular line is : y = 3/4x - 2/4....or 3x - 4y = 2

and ur point (6,4) lies on the perpendicular line <===

6 0

2 years ago

Which number shows 6,312 rounded to the nearest ten? 6,300 6,310 6,320 6,330

Fiesta28 [93]

1 is in the tens place

we look at 2

2 <5 so we leave it alone

6,310

Choice B

7 0

3 years ago

Read 2 more answers

Johnson Chemicals is considering two options for its supplier portfolio. Option 1 uses two local suppliers. Each has a "unique-e

sashaice [31]

Answer:

a) P=0.0175

b) P=0.0189

Step-by-step explanation:

For both options we have to take into account that not only the chance of a "superevent" will disable both suppliers.

The other situation that will disable both is that both suppliers have their "unique-event" at the same time.

As they are, by definition, two independent events, we can calculate the probability of having both events at the same time as the product of both individual probabilities.

a) Then, the probability that both suppliers will be disrupted using option 1 is

$P_1=P_{se}+P_{ue}^2=0.015+(0.05)^2=0.015+0.0025=0.0175$