<span>The horizontal axis in the coordinate plane is called the x-axis. The vertical axis is called the y-axis. The point at which the two axes intersect is called the origin. The origin is at 0 on the x-axis and 0 on the y-<span>axis</span></span>
Answer:
you said sin30 it should say that you can do it with your calculator. unless you need to do it with trigonometric relations. but sin30 should equal .5
Step-by-step explanation:
Answer:
x < -12
General Formulas and Concepts:
<u>Pre-Algebra</u>
Step-by-step explanation:
<u>Step 1: Define</u>
-6x > 72
<u>Step 2: Solve for </u><em><u>x</u></em>
- Divide -6 on both sides: x < -12
Here we see that any value <em>x</em> smaller than -12 would work as a solution to the inequality.
Your on you own with that one buddy sorry bro (5,0)
Let p(x)=x^3+2x^2+kx+3
On dividing p(x) by x-3, the remainder is 21. Therefore,
P(3)=21
Substituting x=3 in p(x)
P(3)=3^3 +2*(3)^2+k*3+3
=27+18+3k+3
=48+3k
We know that, p(3)=21.
So, 48+3k=21
3k=21-48
3k=-27
k=-27/3 =-9
now, p(x) =x^3+2x^2-9x-18
-2 is a factor of p(x) on inspection. Therefore, divide p(x) by x+2 to find the
zeroes of the polynomial.
On dividing, we get the factors to be, (x^2-9)(x+2)
(x^2-3^2)(x+2)
Factorizing using the identity a^2-b^2=(a+b)(a-b) we get,
(x+3)(x-3)(x+2)
Therefore, the zeroes of the polynomials are -3,+3 and -2.