Find the dimensions of a rectangle with perimeter 116 m whose area is as large as possible. (if both values are the same number,
enter it into both blanks.)
1 answer:
The dimensions would be 29 by 29.
To maximize area and minimize perimeter, we make the dimensions as close to equilateral as possible.
Dividing the perimeter by the number of sides, we have
116/4 = 29
This means that both length and width can be 29.
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360/9=40
There are 40 "packs" of 9 students.
40*5=200 for the boys
40*4=160 for the girls
There are 200 boys and 160 girls.
Answer:
a^8 - 12a^4 + 36
= (a^4)^2 - 2*a^4*6 + 6^2
= (a^4 - 6)^2
Answer:
y = 11.54°
Step-by-step explanation:
Reference angle = y°
Opposite side length = 4
Hypotenuse = 20
Apply trigonometric function SOH:
y = 11.536959° ≈ 11.54° (nearest hundredth)
Answer:
The first choice.
Step-by-step explanation:
Your graph should look like one below.
So, difference as in subtract? so, if it is, it would be 15. if it means percent difference, it's about 60%.
