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umka2103 [35]
3 years ago
15

How do I do this I need asap plzzz and thxs

Mathematics
2 answers:
ankoles [38]3 years ago
7 0
Answer is A 

<B = 90 but <D = 29
FinnZ [79.3K]3 years ago
7 0
The answer would be A

Angle B equals 90 degrees since this is a right triangle where as angle D equals 29 degrees as stated in the diagram. Therefor answer A is the only incorrect statement.

Summary= Your answer is A


Detailed Explanation


Both Triangles are congruent, we know this because all the angles are equal to one another. The missing angle in both triangles is 90 degrees, we know this because these are considered right triangles hence the square in the corner. Looking further into the diagram we notice that B=E, F=A, and D=C knowing this we can then go through the process of elimination.

Answer choice D states A=F, since we already found that F does indeed equal A this statement is true therefore its not the answer.

Answer Choice C states ABC=FED this is asking if angle B is equal to angle E which we already found out to be true so this one is incorrect.

Answer Choice B states the line AC=FD since we know these triangles are congruent we know this statement is true, so this answer is also incorrect.

Answer Choice A states B=D this is false since we allready know B=E not D so this is the correct answer.
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Read 2 more answers
A manager randomly selected 25 large cash transactions at a bank that were made in January. The manager then carefully tracked d
Dmitriy789 [7]

Answer:

0.4629 = 46.29% probability that the manager finds more than two such transactions

Step-by-step explanation:

For each transaction, there are only two possible outcomes. Either there is a procedural error, or there is not. The probability of a procedural error on a transaction is independent of any other transaction. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A manager randomly selected 25 large cash transactions at a bank that were made in January.

This means that n = 25

The chance for a procedural error is 10%

This means that p = 0.1

What is the probability that the manager finds more than two such transactions?

This is:

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{25,0}.(0.1)^{0}.(0.9)^{25} = 0.0718

P(X = 1) = C_{25,1}.(0.1)^{1}.(0.9)^{24} = 0.1994

P(X = 2) = C_{25,2}.(0.1)^{2}.(0.9)^{23} = 0.2659

P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0718 + 0.1994 + 0.2659 = 0.5371

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5371 = 0.4629

0.4629 = 46.29% probability that the manager finds more than two such transactions

4 0
3 years ago
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