I'll just help quickly with a couple of expressions that are equivalent.
3(m+5+9m)
If you solve it out, you get 3m+15+27m.
Simply the expression to get 30m+15.
You can regroup to make another expression 5(6m+3) which is also equal.
Answer:
8
Step-by-step explanation:
2.4 - 1.57 = 0.83
Answer:
I have uploaded a picture so you could understand it a little more.
A linear function is when there is a table that gives numbers that represent a function, as shown in the picture.
In the Image, there is a table with a x and y column. And in both columns, there are numbers.
This is what the table looks like in the picture:
<u> x y </u>
0 4 The key is y = 2x + 4
1 6 <------ lets grab the number 1 in the x column and lets
2 8 multiply it by two. Now add four to it, and we will
3 10 have the number 6 in the y column.
4 12
I hope I helped you! God bless :-)
El volumen <em>remanente</em> entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.
<h3>¿Cuál es el volumen remanente entre una caja cúbica vacía y una pelota?</h3>
En esta pregunta debemos encontrar el volumen <em>remanente</em> entre el espacio de una caja <em>cúbica</em> y una esfera introducida en el elemento anterior. El volumen <em>remanente</em> es igual a sustraer el volumen de la pelota del volumen de la caja.
Primero, se calcula los volúmenes del cubo y la esfera mediante las ecuaciones geométricas correspondientes:
Cubo
V = l³
V = (4 cm)³
V = 64 cm³
Esfera
V' = (4π / 3) · R³
V' = (4π / 3) · (2 cm)³
V' ≈ 33.5103 cm³
Segundo, determinamos la diferencia de volumen entre los dos elementos:
V'' = V - V'
V'' = 64 cm³ - 33.5103 cm³
V'' = 30.4897 cm³
El volumen <em>remanente</em> entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.
Para aprender más sobre volúmenes: brainly.com/question/23940577
#SPJ1
Answer:
FALSE
Step-by-step explanation:
In order to be consistent with the system of unit we should decide if we are going to work with the CGS system <em>(centimeter-gram-second)</em> or the MKS system <em>(meter-kilogram-second).
</em>
If we decide to work with the CGS system, the equation of motion would be
8,000x ′′ + 2x = 0; x(0) = 3, x ′ (0) = 0
since 1 Kg = 1,000 g
If we decide to work with the MKS system, the equation of motion would be
8x ′′ + 2x = 0; x(0) = 0.03, x ′ (0) = 0
given that 1 mt = 100 cm
