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2 years ago

What is the area of this triangle in square inches?

Mathematics

1 answer:

adelina 88 [10]2 years ago

3 0

The area of a triangle is found by multiplying the base by the height, then dividing that by 2:

Area = 10 * 7 = 70

70 / 2 = 35 square yards.

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What is the period of this graph?

SCORPION-xisa [38]

Answer:

Period is time between the two peaks.

Period = 4.114 - 1.870

Period = 2.244 seconds

Step-by-step explanation:

4 0

3 years ago

The area of the Pacific Ocean is about 6.0061 x 107 square miles. The area of the Southern Ocean is about 7.8483 x 106 square mi

Scilla [17]

Answer:

A. 8

Step-by-step explanation:

6.0061 x 10^7

/ = 6/8 x 10^7/10^6

7.8483 x 10^6

0.75 x 10^7-6

0.75 x 10^1

A: 0.75 = 7.5 = 8.

5 0

2 years ago

Find the slope of the line

vladimir1956 [14]

Answer:

The slope is 3

Step-by-step explanation:

Rise / Run

3 / 1

= 3

7 0

2 years ago

Read 2 more answers

Solve the system of equations. – 9y + 4x – 11 = 0 - 3y + 10x + 31 = 0

Kruka [31]

value of x =-4 and value of y=-3

(-4,-3) is the solution of system of equations.

Step-by-step explanation:

We need to solve the system of equations

$-9y + 4x-11 = 0- 3y + 10x + 31 = 0$

Rearranging:

$-9y + 4x = 11\,\,\,eq(1)\\- 3y + 10x=- 31 = 0\,\,\,eq(2)$

Multiply eq(2) with 3 and subtract eq(2) from eq(1)

$-9y + 4x = 11\\-9y+30x=-93\\+\,\,\,\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,+\\----------\\-26x=104\\x=\frac{104}{-26}\\x=-4$

Putting value of x = -4 into eq(1)

$-9y + 4x = 11\\-9y+4(-4)=11\\-9y-16=11\\-9y=11+16\\-9y=27\\y=\frac{27}{-9}\\y=-3$

So, value of x =-4 and value of y=-3

(-4,-3) is the solution of system of equations.

Keywords: system of equations.

Learn more about system of equations at:

#learnwithBrainly

5 0

2 years ago

Find the equation for the line that passes through the point (1,-3) and that is parallel to the line with the equation 3/2x-2y=-

kondaur [170]

The equation for the line that passes through the point (1,-3) and that is parallel to the line with the equation $\frac{3}{2}x - 2y = \frac{-17}{2}$ is:

$y = \frac{3}{4}x - \frac{15}{4}$

<h3>Solution:</h3>

Given that line that passes through the point (1, -3) and that is parallel to the line with the equation $\frac{3}{2}x - 2y = \frac{-17}{2}$

We have to find equation of line

The slope intercept form is given as:

y = mx + c

Where "m" is the slope of line and "c" is the y-intercept

Let us first find slope of line containing equation $\frac{3}{2}x - 2y = \frac{-17}{2}$

$\frac{3}{2}x - 2y = \frac{-17}{2}$

Rearrange the above equation into slope intercept form

$\frac{3x}{2} + \frac{17}{2} = 2y\\\\y = \frac{3x}{4} + \frac{17}{4}$

On comparing the above equation with slope intercept form y = mx + c,

$m = \frac{3}{4}$

So the slope of line containing equation $\frac{3}{2}x - 2y = \frac{-17}{2}$ is $m = \frac{3}{4}$

We know that slopes of parallel lines are equal

So the slope of line parallel to line having above equation is also $m = \frac{3}{4}$

Now let us find the equation of line having slope m = 3/4 and passes through point (1 , -3)

Substitute $m = \frac{3}{4}$ and (x, y) = (1 , -3) in slope intercept form

y = mx + c

$-3 = \frac{3}{4}(1) + c\\\\c = -3 - \frac{3}{4}\\\\c = \frac{-15}{4}$

Thus the required equation of line is:

substitute $m = \frac{3}{4}$ and $c = \frac{-15}{4}$ in slope intercept form

$y = \frac{3}{4}x + \frac{-15}{4}\\\\y =\frac{3}{4}x - \frac{15}{4}$

Thus the equation of line is found out

3 0

2 years ago