Question

Prove that the value of expression 9^7 + 3^12 is divisible by 90.

Answer 1

Hey there!

$\bold{\frac{9^7+3^1^2}{90}}$

$\bold{9^7=4,782,969}$

$\bold{3^{12}=531,441}$

$\bold{\frac{4,782,969+531,441}{90}}$

$\bold{4,782,969+531,441=5314410}$

$\bold{\frac{5314410}{90}=69,049}$

$\boxed{\boxed{\bold{59,049}}}$

$\boxed{\boxed{\bold{Answer:3^{10}\times90}}}$

Good luck on your assignment and enjoy your day

~$\bold{LoveYourselfFirst:)}$

Answer 2

Answer:

3^10

Step-by-step explanation:

9^7 + 3^12

Replace 9 with 3^2

(3^2)^7 + 3^12

We know that a^b^c = a^(b*c)

3^(2*7) + 3^12

3^14 +3^12

Factor out 3^12

3^12 (3^2+1)

3^12 (9+1)

3^12(10)

But we need 90 not 10

3^10 * 3^2 (10)

3^10 *9 (10)

3^10 *(90)