The event "Atleast once" is the complement of event "None".
So, the probability that Marvin teleports atleast once per day will the compliment of probability that he does not teleports during the day. Therefore, first we need to find the probability that Marvin does not teleports during the day.
At Morning, the probability that Marvin does not teleport = 2/3
Likewise, the probability tha Marvin does not teleport during evening is also 2/3.
Since the two events are independent i.e. his choice during morning is not affecting his choice during the evening, the probability that he does not teleports during the day will be the product of both individual probabilities.
So, the probability that Marvin does not teleport during the day = 
Probability that Marvin teleports atleast once during the day = 1 - Probability that Marvin does not teleport during the day.
Probability that Marvin teleports atleast once during the day = 
155 - 2⁷ = 27 =3³
155 - 2⁷ = 3³
2⁷ + 3³ =155
The x variable, that is being multiplied.
For perpendicular lines, m1m2 = -1 or m2 = -1/m1; where m1 and m2 are the slopes of the lines.
Here line 1 is 3x - 7y = 42
7y = 3x - 42
y = 3/7 x - 6; Hence m1 = 3/7
m2 = -1/(3/7) = -7/3
Required equation y - y1 = m2(x - x1)
y - (-8) = -7/3(x - (-3))
y + 8 = -7/3(x + 3)
y + 8 = -7/3 x - 7
y = -7/3 x - 7 - 8
y = -7/3 x - 15
Answer:
D
Step-by-step explanation:
Given
x² - 10x = - 36
Solve using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 5)x + 25 = - 36 + 25
(x - 5)² = - 11 ( take the square root of both sides )
x - 5 = ±
( add 5 to both sides )
x = 5 ± i
Thus
x = 5 - i
or x = 5 + i