Answer:
The question is incomplete, the complete question will be:
Suppose you are offered the opportunity to roll a six-sided die, whose faces are 1, 2, 3, 4, 5, and 6. You have no reason to believe one face is any more likely that another. After the roll, you will be paid $1 times and you have the option to throw a die up to three times. You will earn the face value of the die. You have the option to stop after each throw and walk away with the money earned. The earnings are not additive. What is the expected payoff of this game?
Step-by-step explanation:
The answer COULD possibly be letter B
Answer:
x = -1
y = 5
Step-by-step explanation:
x+y=4
3x+7y=32
<em><u>To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.</u></em>
x+y=4,3x+7y=32
<em><u>Choose one of the equations and solve it for x by isolating x on the left hand side of the equal sign.</u></em>
x+y=4
<em><u>Subtract y from both sides of the equation</u></em>.
x=−y+4
<em><u>Substitute −y+4 for x in the other equation, 3x+7y=32.</u></em>
3(−y+4)+7y=32
<em><u>Multiply 3 times −y+4.</u></em>
−3y+12+7y=32
<em><u>Add −3y to 7y.</u></em>
4y+12=32
<em><u>Subtract 12 from both sides of the equation</u></em>.
4y=20
<em><u>Divide both sides by 4</u></em>.
y=5
<em><u>Substitute 5 for y in x=−y+4. Because the resulting equation contains only one variable, you can solve for x directly.</u></em>
x=−5+4
<em><u>Add 4 to −5.</u></em>
x=−1
The answer would be 36:18 and done
Answer:
P(t) = 1000e^(0.01155)t
Step-by-step explanation:
Let the population of barangay be expressed according to the exponential formula;
P(t) = P0e^kt
P(t) is the population of the country after t years
P0 is the initial population
t is the time
If barangay has 1000 initially, this means that P0 = 1000
If the population doubles after 60years then;
at t = 60, P(t) = 2P0
Substitute into the formula
2P0 = P0e^k(60)
2 = e^60k
Apply ln to both sides
ln2 = lne^60k
ln2 = 60k
k = ln2/60
k = 0.01155
Substitute k = 0.01155 and P0 into the expression
P(t) = 1000e^(0.01155)t
Hence an exponential model for barangay's population is
P(t) = 1000e^(0.01155)t