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3 years ago

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Mathematics

1 answer:

Vlad [161]3 years ago

6 0

I’m pretty due the answer $72

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I need help with this

Volgvan

Answer:

72 pi + 48 pi= 120pi (not sure if I am right tho)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

7th grade help me plzzzzz

Gekata [30.6K]

Answer:

fifteen, "number sentence"

Step-by-step explanation:

5 + 5 +5 = 15

4 0

3 years ago

EXTREMELY URGENT GEOMETRY! 15 POINTS!<br><br> PLEASE HELP

zhenek [66]

Answer:

20.3 units

Step-by-step explanation:

AB/CB = BD/AB

9/CB = 4/9

CB = 9×9/4

CB = 81/4 = 20¼ units

20.25 (20.3 units correct to 1 dp)

7 0

3 years ago

A circle has a circumference of 9π what is the diameter?

mixas84 [53]

C=πd where C=circumference, π=the constant pi, and d=diamter

d=C/π and since we are told that C=9π

d=9π/π

d=9

7 0

3 years ago

For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of

Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is $(-1)^{k+1}(\frac{1}{2^{k}})$ .

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as $(-1)^{k+1}(\frac{1}{2^{k}})$ .

where k is from 1 to 10.

By the given expression sequence will be $\frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......$

In this sequence first term "a" = $\frac{1}{2}$

and common ratio in each successive term to the previous term is 'r' = $\frac{\frac{(-1)}{4}}{\frac{1}{2} }$

r = $-\frac{1}{2}$

Since the sequence is infinite and the formula to calculate the sum is represented by

$S=\frac{a}{1-r}$ [Here r is less than 1]

$S=\frac{\frac{1}{2} }{1+\frac{1}{2}}$

$S=\frac{\frac{1}{2}}{\frac{3}{2} }$

S = $\frac{1}{3}$

Now we are sure that the sum of infinite terms is $\frac{1}{3}$ .

Therefore, sum of 10 terms will not exceed $\frac{1}{3}$

Now sum of first two terms = $\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

Now we are sure that sum of first 10 terms lie between $\frac{1}{4}$ and $\frac{1}{3}$

Since $\frac{1}{2}>\frac{1}{3}$

Therefore, Sum of first 10 terms will lie between $\frac{1}{4}$ and $\frac{1}{2}$ .

Option D will be the answer.

3 0

3 years ago