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Sarah read 215 pages of her book during the first week of vacation. During the second week she read62 more pages then the first

Katarina [22]

Answer:

She read 277 pages during the second week.

Step-by-step explanation:

215 + 62.

3 0

3 years ago

Read 2 more answers

Two planes just took off from St. Louis, MO. The first plane is traveling 3.5 times as fast as the second plane. After Traveling

Yanka [14]

Answer:

Speed of first plane is 350 miles per hour

Speed of second plane is 100 miles per hour

Step-by-step explanation:

Let the speed of the second plane be X

Then the speed of the first plane will be 3.5 X

Distance travelled by first plane is 9.5 *X

Distance travelled by second plane is 9.5 * 3.5 X

Difference of distance between the two plane is

$9.5 * 3.5 X - 9.5 *X = 2375\\23.75 X = 2375\\X = 100$ miles per hour

Speed of first plane is 3.5 *100 = 350 miles per hour

Speed of second plane is 100 miles per hour

8 0

3 years ago

Peter has one of each of the following coins in his pocket: a penny, a nickel, a dime, a quarter, and a half-dollar. Four of the

DochEvi [55]

Answer:

10

Step-by-step explanation:

This is a combinations problem, involving factorials.

5!/3!*2!=5*4/2=20/2=10

3 0

4 years ago

How to find the measure of the supplement

Neko [114]

If we know<span> that a set of angles form one of these special relationships, we can </span>determine the measure<span> of the other angle.</span>

8 0

4 years ago

You know that in a specific population of rainbow trout 15% of the individuals carry intestinal parasites. Assume you obtain a r

kicyunya [14]

Answer:

a) 0.2316 = 23.16% probability that 0 carry intestinal parasites.

b) 0.4005 = 40.05% probability that at least two individuals carry intestinal parasites.

Step-by-step explanation:

For each trout, there are only two possible outcomes. Either they carry intestinal parasites, or they do not. Trouts are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

You know that in a specific population of rainbow trout 15% of the individuals carry intestinal parasites.

This means that $p = 0.15$

Assume you obtain a random sample of 9 individuals from this population:

This means that $n = 9$

a. Calculate the probability that __ (last digit of your ID number) carry intestinal parasites.

Last digit is 0, so:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{9,0}.(0.15)^{0}.(0.85)^{9} = 0.2316$

0.2316 = 23.16% probability that 0 carry intestinal parasites.

b. Calculate the probability that at least two individuals carry intestinal parasites.

This is

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{9,0}.(0.15)^{0}.(0.85)^{9} = 0.2316$

$P(X = 1) = C_{9,1}.(0.15)^{1}.(0.85)^{8} = 0.3679$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.2316 + 0.3679 = 0.5995$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5995 = 0.4005$

0.4005 = 40.05% probability that at least two individuals carry intestinal parasites.

5 0

3 years ago