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Sliva [168]
3 years ago
11

Find S15 for 1 + 1.5 + 2.25 + 3.375 + …

Mathematics
1 answer:
Mariulka [41]3 years ago
6 0
By keenly investigating the given above, it is observed that the given is a geometric sequence with first term (a1) equals 1 and common ratio (r) is 1.5. The geometric series can be calculated by the equation, 
  
                                     Sn = a1 x (1 - r^n) / (1 - r)

where n is 15. 

Substituting the known values,
                            <span>Sn = 1 x (1 - 1.5^15) / (1 - 1.5)  = 873.78778
</span>
Therefore, S15 is approximately equal to 873.79. 

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Solve the following system of equations:<br><br> x + 3y = −4<br> x + 5y = −6<br><br> pls and thx
Agata [3.3K]

Answer:

x = -1  y = -1

Step-by-step explanation:

x + 3y = −4

x + 5y = −6

Multiply the first equation by -1

-x - 3y = 4

The add to the second equation to eliminate x

-x - 3y = 4

x + 5y = −6

--------------------

 2y = -2

Divide by 2

2y/2 = -2/2

y = -1

Now solve for x

x+3y = -4

x +3(-1) = -4

x -3 = -4

Add 3 to each side

x-3+3 = -4+3

x = -1

4 0
3 years ago
Read 2 more answers
The sum of 4 and the product of 5 and x is equal to 5 less than the product of 2 and x. What is the value of x?
Alexxandr [17]

Answer:

b. -3

Step-by-step explanation:

i hope this helps :)

7 0
3 years ago
An elevator containing five people can stop at any of seven floors. What is the probability that no two people exit at the same
elena-s [515]

Answer:

Approximately 0.15 (360 / 2401.) (Assume that the choices of the 5 passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 7 floors.)

Step-by-step explanation:

If there is no requirement that no two passengers exit at the same floor, each of these 5 passenger could choose from any one of the 7 floors. There would be a total of 7 \times 7 \times 7 \times 7 \times 7 = 7^{5} unique ways for these 5\! passengers to exit the elevator.

Assume that no two passengers are allowed to exit at the same floor.

The first passenger could choose from any of the 7 floors.

However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only (7 - 1) = 6 floors.

Likewise, the third passenger would have to choose from only (7 - 2) = 5 floors.

Thus, under the requirement that no two passenger could exit at the same floor, there would be only (7 \times 6 \times 5 \times 4 \times 3) unique ways for these two passengers to exit the elevator.

By the assumption that the choices of the passengers are independent and uniform across the 7 floors. Each of these 7^{5} combinations would be equally likely.

Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:

\begin{aligned}\frac{(7 \times 6 \times 5 \times 4 \times 3)}{7^{5}} \approx 0.15\end{aligned}.

5 0
2 years ago
What is the value of the exponential expression below? 36 1/2
Aleksandr [31]

36 1/2 = 6

Given: the exponential expression

6 0
3 years ago
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Find the value of k for x^2 - 2kx+7k -12=0 so that they have two equal roots
Alisiya [41]

Step-by-step explanation:

x^2 -2kx +7k -12 = 0

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so k =3 and k =4

5 0
3 years ago
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