(n*3)+6-(n*2)=n+3
3n+6-2n=n+3
3n-2n-n=3-6 every n on the left and free numbers on the right
0=-3
contradiction, there are no solution
<span>Inflection points are where the function changes concavity. Since concave up corresponds to a positive second derivative and concave down corresponds to a negative second derivative, then when the function changes from concave up to concave down (or vise versa) the second derivative must equal zero at that point. So the second derivative must equal zero to be an inflection point. But don't get excited yet. You have to make sure that the concavity actually changes at that point.</span>
Answer:
Remember, a number a is a zero of the polynomial p(x) if p(a)=0. And a has multiplicity n if the factor (x-a) appear n times in the factorization of p(x).
1. Since -2 is a zero with multiplicity 1, then (x+2) is a factor of the polynomial.
2. Since 1 is a zero with multiplicity 2, then (x-1) is a factor of the polynomial and appear 2 times.
3. Since 5 is a zero with multiplicity 3, then (x-5) is a factor of the polynomial and appear 3 times.
Then, the polynomial function with the zeros described above is
Answer:
B. 88.8
Step-by-step explanation:
let x represent class y
(x+71.2)/2=80 multiply each side by 2
x+71.2=160 subtract 71.2 by both sides
x=88.8
or
trial an error
replace x with each of the numbers and see if it plugs in.
example:
(80.5+71.2)/2=80
151.7/2=80
75.85=80?
false. incorrect
another example:
(88.8+71.2)/2=80
160/2=80
80=80?
true. correct
<h2>
Explanation:</h2><h2 />
When we say "a is at most b" we mean that "a is less than or equal to b" or "a is not greater than b". So let's solve this problem as follows:
Step 1. Twice the difference of a number and 2
Let's call that unknown number as n. Then, twice the difference of a number and 2 is:
Step 2. Twice the difference of a number and 2 is at most -27
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So the mathematical form of the statement <em>twice the difference of a number and 2 is at most -27 </em>is: