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3 years ago

What is the positive solution of 3x2 -10x =0

Mathematics

1 answer:

Dahasolnce [82]3 years ago

6 0

The answer should be:

x=0, 10/3

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What is the range of the function f(x)=3.2x for the domain {-4,-2,0,2,4}

just olya [345]

Answer:

Option A. $\{-12.8,-6.4,0,6.4,12.8\}$

Step-by-step explanation:

we have

$f(x)=3.2x$

we know that

To find the range, substitute each value of x of the domain and find the value of f(x)

For $x=-4$ -----> $f(-4)=3.2(-4)=-12.8$

For $x=-2$ -----> $f(-2)=3.2(-2)=-6.4$

For $x=0$ -----> $f(0)=3.2(0)=0$

For $x=2$ -----> $f(2)=3.2(2)=6.4$

For $x=4$ -----> $f(4)=3.2(-4)=12.8$

therefore

The range is $\{-12.8,-6.4,0,6.4,12.8\}$

5 0

3 years ago

) Every two out of three kids sang at the talent show. What percent of the kids did not sing at the talent show? (round)

SCORPION-xisa [38]

The answer is 33 percent

hope this helps!

4 0

3 years ago

Read 2 more answers

Math help Please!!!!

GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation −2y=3x+7 in the form $y=-\dfrac{3}{2}x-\dfrac{7}{2}.$ Here the slope of the given line is $m_1=-\dfrac{3}{2}.$ If $m_2$ is the slope of perpendicular line, then

$m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.$

Answer 1: $\dfrac{2}{3}$

Part B. The slope of the line y=−2x+3 is -2. Since $-\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2,$ then lines from part A are not parallel to line a.

Since $-2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1,$ both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line $y=\dfrac{x}{4}+5$ is $\dfrac{1}{4}.$ Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then