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il63 [147K]
3 years ago
10

How to solve which fraction is larger 10/13 or 11/14 or 14/15 or 17/18

Mathematics
1 answer:
alexandr402 [8]3 years ago
5 0
To solve these type of problem you have to make the denominator the same or use the claculator.

let us do this problem by making the denominator the same.

\frac{10}{13} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{11}{14} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{14}{15}  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{17}{18} \\\\ \frac{10}{13}\times \frac{3780}{3780} \ \ \ \ \ \ \ \ \ \frac{11}{14} \times \frac{3510}{3510} \ \ \ \ \ \ \ \ \ \frac{14}{15} \times \frac{3276}{3276} \ \ \ \ \ \ \ \ \ \frac{17}{18} \times \frac{2730}{2730}

\frac{37800}{49140} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \    \frac{38610}{49140}  \ \ \ \ \ \ \ \ \ \ \ \ \ \    \frac{45864}{49140}  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \    \frac{46410}{49140}

So, now. the one with the largest numerator is the largest fraction

In this case, \frac{46410}{49140} is the largest which is equal to \frac{17}{18}.

So, the largest fraction is \frac{17}{18}.
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Let:

Vbu= Volume of the buret

Vbk= Volume of the beaker

A buret initially contains 70.00 millimeters of a solution and a beaker initially contains 20.00 ml of the solution the buret drips solution into the Beaker. each drip contains 0.05 mL of solution, therefore:

x = Number of drips

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\begin{gathered} Vbu=70-ax \\ Vbk=20+ax \\ \text{where:} \\ a=0.05 \\ Vbu=70-0.05x \\ Vbk=20+0.05x \end{gathered}

after how many drips will the volume of the solution in the buret and beaker be equal ?​ Vbu = Vbk:

\begin{gathered} Vbu=Vbk \\ 70-0.05x=20+0.05x \\ \text{Solve for x:} \\ 0.1x=70-20 \\ 0.1x=50 \\ x=\frac{50}{0.1} \\ x=500 \end{gathered}

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1 year ago
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aleksklad [387]

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Step-by-step explanation:

2x+y=4                  4x+2y=8

2x     =/2                     2y= /2

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lesya692 [45]
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however if you wanted to really show the working out, it looks like this:

y=mx+c

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subsitute one of the coordinates into y=mx+c

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so then y=-1



4 0
3 years ago
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