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il63 [147K]
3 years ago
10

How to solve which fraction is larger 10/13 or 11/14 or 14/15 or 17/18

Mathematics
1 answer:
alexandr402 [8]3 years ago
5 0
To solve these type of problem you have to make the denominator the same or use the claculator.

let us do this problem by making the denominator the same.

\frac{10}{13} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{11}{14} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{14}{15}  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{17}{18} \\\\ \frac{10}{13}\times \frac{3780}{3780} \ \ \ \ \ \ \ \ \ \frac{11}{14} \times \frac{3510}{3510} \ \ \ \ \ \ \ \ \ \frac{14}{15} \times \frac{3276}{3276} \ \ \ \ \ \ \ \ \ \frac{17}{18} \times \frac{2730}{2730}

\frac{37800}{49140} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \    \frac{38610}{49140}  \ \ \ \ \ \ \ \ \ \ \ \ \ \    \frac{45864}{49140}  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \    \frac{46410}{49140}

So, now. the one with the largest numerator is the largest fraction

In this case, \frac{46410}{49140} is the largest which is equal to \frac{17}{18}.

So, the largest fraction is \frac{17}{18}.
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A clinical trial was conducted to test the effectiveness of the drug zopiclone for treating insomnia in older subjects. Before t
aleksklad [387]

Answer:

We cannot say that the mean wake time are different before and after the treatment, with 98% certainty. So the zopiclone doesn't appear to be effective.

Step-by-step explanation:

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Knowing that t_{0.99,15} = 2.602:

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The sum of the first number cubed and the second number is 500 and the product is a maximum.
soldier1979 [14.2K]

We are given the following information:

the sum of the first number cubed and the second number is 500

their product is a maximum

We are looking for the 2 missing numbers.

To answer this, let's represent the two numbers as x and w.

From the given, we can form the following equation:

x^3+w=500

We can then express y as:

w=500-x^3

We can express their product as:

x(500-x^3)=500x-x^4

To find the maximum value of x, let's solve for the derivative of -x^4 + 500 x.

\begin{gathered} f(x)=-x^4+500x \\ f^{\prime}(x)=-4x^3+500 \end{gathered}

Then we solve for the value of x where f'(x) = 0.

\begin{gathered} -4x^3+500=0 \\ -4x^3=-500 \\ x^3=125 \\ x=5 \end{gathered}

Then we use x = 5 to solve for the second number, w.

\begin{gathered} w=500-x^3 \\ w=500-5^3 \\ w=500-125 \\ w=375 \end{gathered}

Therefore, the two numbers are 5 and 375.

3 0
1 year ago
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