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3 years ago

What is the area of a circle with a radius of 7 cm? (Use 3.14 and round to the nearest tenth.)

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

5 0

A = πr²

A = π7²

A = 49π

A = 49.3,14

A = 153,86

Rounding to the nearest tenth

A = 153,9 cm²

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The expression 36 ÷ 6 • 2 + 1 is equal to _____. 2 4 13 18

NeTakaya

Answer:

Step-by-step explanation:

36/6 · 2 + 1

6 ·2 + 1

12 + 1 = 13

answer is 13

7 0

3 years ago

Which translation shifts the graph of f(x)=3x+3 onto g(x)=3x-3

WARRIOR [948]

The translation that flips sides

5 0

3 years ago

Rita drank the following ounces of milk during the last week

Andre45 [30]

Answer:

Mean = 14.14

Mode = 14

Median = 14

Range = 16

Step-by-step explanation:

Given Data Set : 18 , 14 , 10 , 22, 14 , 15 and 6

Identifying the mean

Mean = Sum of given data values / total # of given values

Here sum of given data values = 18 + 14 + 10 + 22 + 14 + 15 + 6 = 99

And there are 7 given data values

So mean = 99 / 7 =

14.14

( approximately )

Identifying the mode

The mode is the number that appears most often

14 appears twice, which is the most times out of any other value

Hence, the mode is

Identifying the median

The median is the middle number in terms of value

To make this easier, its best to order the given values from least to greatest
Doing so we acquire 6 , 10 , 14 , 14 , 15 , 18 , 22

Then you go to the middle of the listed terms.

Doing so we would end up with 14 being in the middle

Hence the median is

Identifying the range

Range = largest given value - smallest given value

Here the most rita drank was 22 ounces and the least amount of milk she drank was 6 ounces

So the range would be 22 - 6 =

ounces

And we are done!

3 0

2 years ago

a) find center of mass of a solid of constant density bounded below by the paraboloid z=x^2+y^2 and above by the plane z=4.(b) F

slava [35]

Answer: x-bar = y-bar = 0 whereas z-bar = 8/3

M= (c^2)/8 which is intern equal to 2 $\sqrt{2}$

Step-by-step explanation:

Find the area, by setting the limits as

= $4\cdot \int _0^{\frac{\pi }{2}}\int _0^2\int _{r^2}^4\:rdzdrd\theta$

$=4\cdot \int _0^{\frac{\pi }{2}}\int _0^2r\cdot \:4-r^3drd\theta$

$=4\cdot \int _0^{\frac{\pi }{2}}4d\theta$

$=8\pi$

Therefore;

Mxy= $\int _0^{2\pi }\int _0^2\int _{r^2}^4\:zrdzdrd\theta$

z-bar = 8/3

M= 8 $\pi$ dividing it into two volume gives us = 4 $\pi$

means $4\pi =\int _0^{2\pi }\int _0^{\sqrt{c}}\int _r^c\:rdzdrd\theta$

$4\pi =\left(\pi c^2-2\pi \frac{c^{\frac{3}{2}}}{3}\right)$

c=2 $\sqrt{2}$

5 0

3 years ago

Please help if can thank you :)

Evgesh-ka [11]

2*(1/2*8 inches*4 inches)+10 inches*4 inches

4 0

3 years ago